Chapter 13.3, Problem 35PPS

To determine

To find: Distance travelled by the rock.

Answer to Problem 35PPS

Distance travelled by the rock $=x=10.15$ meters

Explanation of Solution

Given information:

The equation that represents the horizontal distance of the rock is

  $x=v_0\left(\cos \left(\theta \right)\right)t$

Where

  $v_0$ is the initial velocity

  $\theta$ is the angle at which it is shot

  $t$ is the time in seconds.

  $v_0=6$ meters per second

  $\theta ={65}^0$

  $t=4$ seconds

Given

  $v_0=6$ meters per second

  $\theta ={65}^0$

  $t=4$ seconds On substituting values

We get

  $\begin{array}{l}x=v_0\left(\cos \left(\theta \right)\right)t\\ \Rightarrow x=\left(6\right)\left(\cos \left({65}^0\right)\right)\left(4\right)\\ \Rightarrow x=\left(6\right)\left(0.423\right)\left(4\right)\\ \Rightarrow x=10.15\end{array}$

Therefore,

Distance travelled by the rock $=x=10.15$ meters