Explanation Given Information: The equation of the parabola is y = ( x − 4 ) 2 + 2 . Consider the equation, y = ( x − 4 ) 2 + 2 The parabola having equation y = a ( x − h ) 2 + k will have vertical axis of symmetry. So that, the provided equation has vertical axis of symmetry. Now the parabola having equation of the form y = a ( x − h ) 2 + k , then if a > 0 the parabola will open upward and if a < 0 parabola opens downward. So, rewrite the provided equation as y = 1 ( x − 4 ) 2 + 2 and compare to find a = 1 . Therefore, as a > 0 the parabola will open upward. Now consider the provided equation y = ( x − 4 ) 2 + 2 to make a required table to draw a graph, For x = − 2 , y = ( − 2 − 4 ) 2 + 2 = 36 + 2 = 38 Therefore, the coordinate is ( − 2 , 38 ) . For x = − 1 , y = ( − 1 − 4 ) 2 + 2 = 25 + 2 = 27 Therefore, the coordinate is ( − 1 , 27 ) . For x = 0 . y = ( 0 − 4 ) 2 + 2 = 16 + 2 = 18 Therefore, the coordinate is ( 0 , 18 )

6th Edition

ISBN: 9781260673531

Author: Miller, Julie, O'Neill, Molly, Hyde, Nancy

Publisher: McGraw-Hill Education

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Chapter 13.2, Problem 33PE

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The parabola y=(x−4)2+2 has axis vertical or horizontal axis of symmetry and then whether it opens upward, downward, left or right.

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Chapter 13.2, Problem 32PE

Chapter 13.2, Problem 34PE

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The parabola y = ( x − 4 ) 2 + 2 has axis vertical or horizontal axis of symmetry and then whether it opens upward, downward, left or right.

Solution Summary: The author explains that the parabola y=(x-4)2+2 has axis vertical or horizontal symmetry and will open upward, downward, left or right.

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The parabola y=(x−4)2+2 has axis vertical or horizontal axis of symmetry and then whether it opens upward, downward, left or right.

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