
Concept explainers
a.
Find equation of parallel line.
a.

Answer to Problem 75E
y=−34x+38
Explanation of Solution
Given information:
Write equations of the lines through the given point parallel to given line.
3x+4y=7
(−23,78)
Calculation:
Consider the given points on line.
3x+4y=7
(−23,78)
The equation of line with slope m and given point on the line is,
m=y−y1x−x1
If the slopes of two non vertical lines are equal then lines are parallel.
m1=m2
If the slopes of two non vertical lines are negative reciprocal of each other then lines are perpendicular.
m1=−1m2
Now compare given line with standard equation of line,
y=mx+c Where m is slope and c is intercept.
3x+4y=7
y=−34x+74m=−34
A line parallel to the given line will have slope equal to the given line and it will pass through the given point (−23,78)
So,
y=m1x+cm1=mm1=−34y=−34x+c
Substitute the given points in above eqation,
y=−34x+c78=−34(−23)+cc=38y=−34x+38
Hence the line is.
y=−34x+38
b.
Find equation of perpendicular line.
b.

Answer to Problem 75E
y=43x+12772
Explanation of Solution
Given information:
Write equations of the lines through the given point perpendicular to the given line..
3x+4y=7
(−23,78)
Calculation:
Consider the given points on line.
3x+4y=7
(−23,78)
The equation of line with slope m and given point on the line is,
m=y−y1x−x1
If the slopes of two non vertical lines are equal then lines are parallel.
m1=m2
If the slopes of two non vertical lines are negative reciprocal of each other then lines are perpendicular.
m1=−1m2
Now compare given line with standard equation of line,
3x+4y=7
y=mx+c Where m is slope and c is intercept.
y=−34x+74m=−34
A line perpendicular to the given line will have slope equal to the given line and it will pass through the given point (−23,78)
So,
y=m2x+cm2=−1mm2=43y=43x+c
Substitute the given points in above eqation,
y=43x+c78=43(−23)+cc=12772y=43x+12772
Hence the line is.
y=43x+12772
Chapter 1 Solutions
EBK PRECALCULUS W/LIMITS
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