Modern Physics
3rd Edition
ISBN: 9781111794378
Author: Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher: Cengage Learning
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Chapter 13, Problem 47P
To determine
The reason why electrons cannot reside inside the nucleus using uncertainty principle.
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V= 0
Vo
II
E
X
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Consider a neutron With Mass M And Energy E in the nucleus As
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(II). Calculate the normalized wave function neutrons in each of these
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Assume a nucleus X2. What
are the possible
spin
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c. Write the mathematical expression for the radial probability function. The radial probability function for
any orbital is zero at the nucleus, it also approaches zero at long distance from the nucleus. Explain
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Chapter 13 Solutions
Modern Physics
Ch. 13.4 - Prob. 1ECh. 13 - Prob. 1QCh. 13 - A proton precesses with a frequency p in the...Ch. 13 - Prob. 3QCh. 13 - Prob. 4QCh. 13 - Prob. 5QCh. 13 - Prob. 7QCh. 13 - Prob. 8QCh. 13 - Prob. 9QCh. 13 - What fraction of a radioactive sample has decayed...
Ch. 13 - Prob. 11QCh. 13 - Prob. 12QCh. 13 - Prob. 13QCh. 13 - Prob. 14QCh. 13 - Prob. 15QCh. 13 - Prob. 16QCh. 13 - Prob. 17QCh. 13 - Prob. 18QCh. 13 - Prob. 19QCh. 13 - Prob. 20QCh. 13 - Prob. 21QCh. 13 - Prob. 22QCh. 13 - Prob. 23QCh. 13 - Prob. 25QCh. 13 - Prob. 26QCh. 13 - Prob. 27QCh. 13 - Prob. 28QCh. 13 - Prob. 1PCh. 13 - Prob. 2PCh. 13 - Prob. 3PCh. 13 - Prob. 4PCh. 13 - Prob. 5PCh. 13 - Prob. 6PCh. 13 - Prob. 7PCh. 13 - Prob. 8PCh. 13 - Prob. 9PCh. 13 - Prob. 10PCh. 13 - Prob. 11PCh. 13 - Prob. 12PCh. 13 - Prob. 13PCh. 13 - Prob. 14PCh. 13 - Prob. 15PCh. 13 - Prob. 16PCh. 13 - Prob. 17PCh. 13 - Prob. 18PCh. 13 - Prob. 19PCh. 13 - Prob. 20PCh. 13 - Prob. 21PCh. 13 - Prob. 22PCh. 13 - Prob. 23PCh. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 27PCh. 13 - Prob. 28PCh. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - Prob. 31PCh. 13 - Prob. 32PCh. 13 - Prob. 33PCh. 13 - Prob. 34PCh. 13 - Prob. 35PCh. 13 - Prob. 36PCh. 13 - Prob. 37PCh. 13 - Prob. 38PCh. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - Prob. 43PCh. 13 - Prob. 44PCh. 13 - Prob. 45PCh. 13 - Prob. 46PCh. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - Prob. 50PCh. 13 - Prob. 51PCh. 13 - Prob. 52PCh. 13 - Prob. 53PCh. 13 - Prob. 54PCh. 13 - Prob. 55PCh. 13 - Prob. 56PCh. 13 - Prob. 57PCh. 13 - Prob. 58PCh. 13 - Prob. 59PCh. 13 - Prob. 60PCh. 13 - Prob. 61P
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- (a) An aspiring physicist wants to build a scale model of a hydrogen atom for her science fair project. If the atom is 1.00 m in diameter, how big should she try to make the nucleus? (b) How easy will this be to do?arrow_forward(a) What voltage must be applied to an X-ray tube to obtain 0.0100-fm-wavelength X-rays for use in exploring the details of nuclei? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forwardUsing the principle of precision, prove the impossibility of an electron inside the nucleus, noting that the nucleus has a radius of 1x10-14 marrow_forward
- a) Calculate the uncertainty in momentum for a proton confined to a nucleus of radius 6.0fm b) What is the kinetic energy of a photon with that momentum. c) Suppose a photon in that nucleus had a kinetic energy of 5.6MeV. If the photon were represented by a de Broglie wave, how many wavelengths could fit across the diameter of the nucleus?arrow_forwardUse the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m = 1.67493x10-27 kg = 1.008665 u = 939.57 MeV/c² . ¹H: mH = 1.67353x10-27 kg = 1.007825 u = 938.78 MeV/c² 1 1 u = 1.6605x10-27 kg = 931.5 MeV/c² . Consider the following decay: 239 Pu 235 U+ a. 239 Pu has a mass of 239.0521634 u, 235 U has a mass of 235.0439299 u, and a has a mass of 4.002603 u. 94 92 94 92 Determine the disintegration energy (Q-value) in MeV. Q = Determine the binding energy (in MeV) for 239 Pu. 94 EB =arrow_forwardUse the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m,= 1.67493x1027 kg= 1.008665 u = 939.57 MeVIC H: my = 1.67353x10 27 kg = 1.007825 u = 938.78 MeVic 1u= 1.6605x10-27 kg = 931.5 MeVic? Consider the following decay: 211 At 207 Bi + a. 211 At has a mass of 210.9874963 u, 207 Bi has a mass of 206.981593 u, and a has a mass of 4.002603 u. 85 83 85 83 Determine the disintegration energy (Q-value) in MeV. Determine the binding energy (in MeV) for 211 At. 85 EB =arrow_forward
- Determine the electrical potential energy of the protons in a nucleus if it is assumed that the charge is uniformly spherically distributed. and compare this with the form of the coulomb term in the liquid drop model. - ac é z (1arrow_forwardnucleus emits an alpha particle with kinetic evergy = 4.20 MeV. What is the daughter nucleus, and what is the approximate atomic mass (in u) of the daughter atom? ignore recoil of the daughter nucleus. if the image doesnt come up properly it is 92^238 Uarrow_forward
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