Chapter 1.3, Problem 38E

To determine

To solve: The system of linear equations in the variable.

Answer to Problem 38E

The value of $x=6$ and $y=2$ .

Explanation of Solution

Given Information: The equations are given as:

  $\begin{array}{l}y-x=-4\\ 4x+y=26\end{array}$

The given equations are.

  $y-x=-4$ ----------------- (i)

  $4x+y=26$ -------------------(ii)

Subtracting equation (ii) from (i)

  $\begin{array}{l}(-x+y)-(4x+y)=-4-26\\ -x+y-4x-y=-30\\ -5x=-30\\ x=\frac{30}{5}\\ x=6\end{array}$

Put $x=6$ in equation (i)

  $\begin{array}{l}y-6=-4\\ y=-4+6\\ y=2\end{array}$

Thus, value of $x=6$ and $y=2$ .