Java Programming
9th Edition
ISBN: 9780357238530
Author: Joyce Farrell
Publisher: Cengage Limited
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Question
Chapter 13, Problem 1RQ
Program Plan Intro
To find which of the given statements is correct.
Expert Solution & Answer
Program Description Answer
b. Volatile storage is lost when a computer loses power.
Explanation of Solution
Explanation:
Volatile Storage:
Volatile storage, also known as volatile memory, refers to computer memory that requires a constant power source to maintain its contents. When a computer loses power, the contents of volatile storage are lost. Examples of volatile storage include RAM (Random Access Memory) and cache memory.
Non-volatile Storage:
In contrast, non-volatile storage, such as hard disk drives (HDD) and solid-state drives (SSD), retains its data even when the power is turned off. This is because non-volatile storage uses permanent storage media to store data, such as magnetic disks or flash memory. It is important to understand the difference between volatile and non-volatile storage, as volatile storage is used for the temporary storage of data that is being actively processed by the computer, while non-volatile storage is used for long-term storage of data that needs to be retained even after the power is turned off.
Conclusion:
Hence, the correct option is option (b).
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Consider the following scenario in which host 10.0.0.1 is communicating with an external SMTP mail server at IP
address 128.119.40.186.
NAT translation table
WAN side addr
LAN side addr
(c), 5051
(d), 3031
S: (e),5051
SMTP
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D (f.(g)
10.0.0.4
server
138.76.29.7
128.119.40.186
(a) is the source IP address at A, and its value.
S: (a),3031
D: (b), 25
10.0.0.1
A
10.0.0.2.
1. 138.76.29.7
10.0.0.3
6.3A-3. Multiple Access protocols (3). Consider the figure below, which shows the arrival of 6
messages for transmission at different multiple access wireless nodes at times t=0.1, 1.4, 1.8, 3.2,
3.3, 4.1. Each transmission requires exactly one time unit.
1
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t=1.0
t-2.0
t-3.0
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t=4.0
t-5.0
For the CSMA protocol (without collision detection), indicate which packets are successfully
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channel busy, then that node will not attempt a retransmission of that packet until sometime after
t=5. Hint: consider propagation times carefully here. (Note: You can find more examples of problems similar to this here B.]
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Just wanted to know, if you had a scene graph, how do you get multiple components from a specific scene node within a scene graph? Like if I wanted to get a component from wheel from the scene graph, does that require traversing still?
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Chapter 13 Solutions
Java Programming
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