Chapter 1.3, Problem 17PPSE

Solution

To state: The expression $-k^2-\left(3k-5n\right)+4n$ for the values $k=-1\text{and}n=-2$ .

The resultant answer is $-16$ .

Given information:

The given expression is $-k^2-\left(3k-5n\right)+4n$ .

Explanation:

Consider the given expression $-k^2-\left(3k-5n\right)+4n$ :

Substitute the values of variable k and n as $-1\text{and}-2$ into the given expression,

  $-{\left(-1\right)}^2-\left(3\left(-1\right)-5\left(-2\right)\right)+4\left(-2\right)$

Multiply,

  $-1-\left(-3+10\right)-8$

Perform operation within grouping symbols,

  $-1-7-8$

Now add and subtract from left to right,

  $-8-8$

Add and subtract from left to right,

  $-16$

Therefore, $-16$ is the resultant value of the expression $-k^2-\left(3k-5n\right)+4n$ .