Biological Science, Books a la Carte Plus Mastering Biology with Pearson eText -- Access Card Package (6th Edition)
6th Edition
ISBN: 9780134296029
Author: Scott Freeman, Kim Quillin, Lizabeth Allison, Michael Black, Greg Podgorski, Emily Taylor, Jeff Carmichael
Publisher: PEARSON
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Chapter 13, Problem 15PIAT
If the results showing increased aneuploidy in older mice can be related to humans, roughly what age in women would correspond to 15-month-old female mice (see Figure 13.13)?
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In drosophila, a recessive mutation (m-) of a maternal effect gene results in an abnormal phenotype wherein homozygous (m-m-) females produce eggs that cannot support embryonic development. Homozygous (m-m-) males, however, can still produce viable sperm.
(A) Using m+ to denote a normal gene, determine the genotypes and phenotypes of the F1s produce by a cross between a heterozygous female and a recessive male.
(B) From the offspring, backcross the recessive female with the paternal strain. What are the genotypes and phenotypes of the F2s?
(C) If m-m- females produce useless eggs, then how are m-m- produced?
In drosophila, a recessive mutation (m-) of a maternal effect gene results in an abnormal phenotype wherein homozygous (m-m-) females produce eggs that cannot support embryonic development. Homozygous (m-m-) males, however, can still produce viable sperm. Using m+ to denote a normal gene, determine the genotypes and phenotypes of the F1s produce by a cross between a heterozygous female and a recessive male. From the offspring, backcross the recessive female with the paternal strain.
1. What are the genotypes and phenotypes of the F2s?
2. If m-m- females produce useless eggs, then how are m-m- produced?
In drosophila, a recessive mutation (m-) of a maternal effect gene results in an abnormal phenotype wherein homozygous (m-m-) females produce eggs that cannot support embryonic development. Homozygous (m-m-) males, however, can still produce viable sperm. Using m+ to denote a normal gene, determine the genotypes and phenotypes of the F1s produce by a cross between a heterozygous female and a recessive male. From the offspring, backcross the recessive female with the paternal strain. What are the genotypes and phenotypes of the F2s? Show COMPLETE cross for both cases. Â
If m-m- females produce useless eggs, then how are m-m- produced?
Chapter 13 Solutions
Biological Science, Books a la Carte Plus Mastering Biology with Pearson eText -- Access Card Package (6th Edition)
Ch. 13 - CAUTION What are homologous chromosomes? a....Ch. 13 - What is an outcome of genetic recombination? a....Ch. 13 - What proportion of chromosomes in a man's skin...Ch. 13 - Nondisjunction that leads to problems in offspring...Ch. 13 - Explain the relationship between homologous...Ch. 13 - If you followed a woman's cells through meiosis,...Ch. 13 - 7. CAUTION Dogs have 78 chromosomes in their...Ch. 13 - Prob. 8TYUCh. 13 - QUANTITATIVE Meiosisresults in independent...Ch. 13 - 10. PROCESS OF SCIENCE A species of rotifer, a...
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- A maternal effect gene in Drosophila, called torso, is found as a recessive allele that prevents the correct development of anterior- and posterior-most structures. A wild-type (homozygous) male is crossed to a female of unknown genotype. This mating produces 100% larva that are missing their anterior- and posterior-most structures and therefore die during early development. What is the genotype and phenotype of the female fly in this cross? What are the genotypes and phenotypes of the female fly’s parents? Show COMPLETE cross.arrow_forwardA maternal effect gene in Drosophila, called torso, is found as a recessive allele that prevents the correct development of anterior- and posterior-most structures. A wild-type (homozygous) male iscrossed to a female of unknown genotype. This mating produces 100% larva that are missing theiranterior- and posterior-most structures and therefore die during early development. What is the genotype and phenotype of the female fly in this cross? What are the genotypes andphenotypes of the female fly’s parents? Show COMPLETE cross.  Maternal genotype:Paternal genotype:F1 genotype:F1 phenotype:arrow_forwardA female Drosophila with the mutant phenotype 'notched wings' was mated to a wild type male. Two-thirds of the progeny were female. Half of the females had notched wings and the other half had wild type wings and all the male progeny had wild type wings. When the notched progeny were mated to their wild type brothers, the same results were obtained. Explain.arrow_forward
- In Drosophila, a heterozygous female for the X-linkedrecessive traits a, b, and c was crossed to a male that phenotypically expressed a, b, and c. The offspring occurred inthe following phenotypic ratios.+ b c              460a + +              450a b c               32+ + +               38a + c               11+ b +                9 No other phenotypes were observed.(a) Determine the correct sequence and construct amap of these genes on the X chromosome ?arrow_forwardIn Drosophila, a heterozygous female for the X-linkedrecessive traits a, b, and c was crossed to a male that phenotypically expressed a, b, and c. The offspring occurred inthe following phenotypic ratios.+ b c              460a + +              450a b c               32+ + +               38a + c               11+ b +                9 No other phenotypes were observed.(a) What is the genotypic arrangement of the alleles ofthese genes on the X chromosome of the female?arrow_forwardVermillion eye color in Drosophila sp. is a sex-linked recessive trait. What phenotype would be found in this progeny of a cross between a vermillion female and a wild type male?arrow_forward
- Two Drosophila flies that had normal (transparent, long) wings were mated. In the progeny, two new phenotypes appeared, dusky wings (having a semi-opaque appearance) and clipped wings (with squared ends). The progeny were as follows: Females: 179 transparent, long 58 transparent, clipped Males: 92 transparent, long 89 dusky, long 28 transparent, clipped 31 dusky, clipped a) Provide a genetic explanation for these results, showing genotypes of parents and of all progeny classes under your model. b) Design a test for your model.arrow_forwardThe nuclear DNA content of a single sperm cell in Drosophila melanogaster is approximately 0.18 picogram. What would be the expected nuclear DNA content of a primary spermatocyte in Drosophila? What would be the expected nuclear DNA content of a somatic cell (non-sex cell) in the G1 phase? What would be the expected nuclear DNA content of a somatic cell at metaphase?arrow_forwardIn Drosophila, a heterozygous female for the X-linkedrecessive traits a, b, and c was crossed to a male that phenotypically expressed a, b, and c. The offspring occurred inthe following phenotypic ratios.+ b c              460a + +              450a b c               32+ + +               38a + c               11+ b +                9 No other phenotypes were observed.(a) What progeny phenotypes are missing? Why?arrow_forward
- A male Drosophila with wild-type phenotype is discovered to have only seven chromosomes, whereas normally 2n = 8. Close examination reveals that one member of chromosome IV (the smallest chromosome) is attached to (translocated to) the end of chromosome II. If this male mates with a female with a normal chromosome composition who is homozygous for the recessive chromosome IV mutation eyeless (genotype = ee), what would be the eye genotypes, eye phenotypes, and total number of chromosomes in all potential offspring if the male is homozygous for the wild-type allele (EE)? put a table for punnet squarearrow_forwardA male Drosophila with wild-type phenotype is discovered to have only seven chromosomes, whereas normally 2n = 8. Close examination reveals that one member of chromosome IV (the smallest chromosome) is attached to (translocated to) the end of chromosome II. If this male mates with a female with a normal chromosome composition who is homozygous for the recessive chromosome IV mutation eyeless (genotype = ee), what would be the eye genotypes, eye phenotypes, and total number of chromosomes in all potential offspring if the male is homozygous for the wild-type allele (EE)?arrow_forwardUsing Drosophila notation: A.) Diagram the genotype of a female fly that is recessive for apterus (ap, chromosome 2), heterozygous wild-type for black (b, chromosome 2), recessive for forked (f, x-chromosome), and homozygous wild type for rosy (ry, chromosome 3). B.) Diagram the genotype of a male fly that is heterozygous for clot (ct) eyes (an autosomal gene) and has yellow (y) body color (x-linked gene).arrow_forward
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