Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 13, Problem 13.5P
For the same data given in Problem 13.4, determine the load-carrying capacity of the drilled shaft, limiting the settlement to 10.0 mm.
13.4 Determine the ultimate load-carrying capacity of the drilled shaft shown in Figure P13.4, using the Reese and O’Neill (1989) method.
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Chapter 13 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Determine the ultimate load-carrying capacity of...Ch. 13 - For the same data given in Problem 13.4, determine...Ch. 13 - Prob. 13.6PCh. 13 - A 3 ft diameter straight drilled shaft is shown in...Ch. 13 - Prob. 13.8PCh. 13 - Figure P13.9 shows a drilled shaft extending into...Ch. 13 - A free-headed drilled shaft is shown in Figure...
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- Determine the ultimate load-carrying capacity of the drilled shaft shown in Figure P13.4, using the Reese and ONeill (1989) method.arrow_forwardFor the drilled shaft described in Problem 19.7, determine these values: a. The ultimate load-carrying capacity b. The load-carrying capacity for a settlement of 25 mm Use the procedure outlined in Section 19.8. 19.7 Figure 19.16 shows a drilled shaft without a bell. Here, L1 = 6 m, L2 = 7 m, Ds = 1.5 m, cu(1) = 50 kN/m2, and cu(2) = 75 kN/m2. Find these values: a. The net ultimate point bearing capacity. Use Eqs. (19.23) and (19.24) b. The ultimate skin resistance. Use Eqs. (19.26) and (19.28) c. The working load, Qw (FS = 3) FIG. 19.16arrow_forwardA free-headed drilled shaft is shown in Figure P13.10. Let Qg = 260 kN, Mg = 0, = 17.5 kN/m3, = 35, c' = 0, and Ep = 22 106 kN/m2. Determine a. The ground line deflection, xo b. The maximum bending moment in the drilled shaft c. The maximum tensile stress in the shaft d. The minimum penetration of the shaft needed for this analysisarrow_forward
- For the drilled shaft described in Problem 19.7, estimate the total elastic settlement at working load. Use Eqs. (18.45), (18.47), and (18.48). Assume that Ep = 20 106 kN/m2, s = 0.3, Es = 12 103 kN/m2, = 0.65 and Cp = 0.03. Assume 80% mobilization of skin resistance at working load. (See Part c of Problem 19.7) 19.7 Figure 19.16 shows a drilled shaft without a bell. Here, L1 = 6 m, L2 = 7 m, Ds = 1.5 m, cu(1) = 50 kN/m2, and cu(2) = 75 kN/m2. Find these values: a. The net ultimate point bearing capacity. Use Eqs. (19.23) and (19.24) b. The ultimate skin resistance. Use Eqs. (19.26) and (19.28) c. The working load, Qw (FS = 3) FIG. 19.16arrow_forwardA 3 ft diameter straight drilled shaft is shown in Figure P13.7. Determine the load-carrying capacity of the drilled shaft with FS = 3. Take / as 0.8 for the sand.arrow_forwardFigure P13.9 shows a drilled shaft extending into clay shale. Given: qu (clay shale) = 1.81 MN/m2. Considering the socket to be rough, estimate the allowable load-carrying capacity of the drilled shaft. Use FS = 4. Use the Zhang and Einstein procedure.arrow_forward
- A free-headed drilled shaft, shown in Figure 4, has an elastic modulus, Ep = 20,000 MPa. M, = 880 kN m Q = 245 kN, Sand at = 19 kN/m3 O' = 34° 1.2 m Figure 4 (a) Determine the ground line deflection, x.arrow_forwardQ2/A standard penetration test was performed in a 150 mm diameter borehole at a depth of 9.5 m below the ground surface. The driller used a UK-style automatic trip hammer, a standard SPT sampler and a 10-m drill rod. The blow counts obtained in the field were as follows: 0-150mm = 4 blows: 150-300mm = 7 blows; 300-450mm = 12 blows. The soil is normally consolidated fine sand with a unit weight of 18.0 kN/m³ and D50 = 0.4 mm. The ground water table is at a depth of 15 m. Compute: (a) N60, (b) (N1)60, (c) D.%, (d) , and (e) denseness of the fine sand.arrow_forwardRefer to Figure 11.26b. For the drilled shaft with bell, given:Thickness of active zone, Z = 9 mDead load = 1500 kN Live load = 300 kNDiameter of the shaft, Ds = 1 mZero swell pressure for the clay in the active zone = 600 kN/m2Average angle of plinth-soil friction, Φ'ps = 20°Average undrained cohesion of the clay around the bell = 150 kN/m2. Determine the diameter of the bell, Db. A factor of safety of 3 against uplift is required with the assumption that dead load plus live load is equal to zero.arrow_forward
- A drilled shaft designed in accordance with the AASHTO code must support the following downward and uplift axial design loads: P = 850 k, Pup. = 270 k. The soil profile consists of: Undrained Shear Strength, s,, (lb/ft²) Depth (ft) Soil Description Unit Weight, y (lb/ft³) N60 0-15 Clayey silt 115 1200 15-35 Silty clay 112 1800 35-55 Sandy silt (nonplastic) 115 24 55-80 Silty sand 124 43 Practice Problems 597 The groundwater is at a depth of 50 ft. Using the AASHTO resistance factors, select a diameter and depth for a single drilled shaft to support these design loads. Use a load factor of 0.9 on the weight of the shaft. Note there are many different diameter-length combinations that would be satisfactory, but select one that you think would be most appropriate.arrow_forwardA triaxial test was performed on a saturated soil and failed under a normal stress of 150 kPa. If the chamber confining pressure is zero and the failure plane makes an angle of 52°... Q: What is the shearing stress at the failure plane in kPa? Round off your answer to the next whole number.arrow_forwardThe blow counts for an SPT test at a depth of 6 m in a coarse-grained soil at every 0.152 m are 10, 10 and 10. A donut automatic trip hammer and a standard sampler were used in a borehole 152 mm in diamneter. The SPT N value is: O 1.8 O 2.20 O 3. 10 O 4.5 QUESTION 14 In Bernoulli's equation the Velocity Head (velocity) can be ignored because O 1. Too large. O 2. To small. O 3. Not important. O 4. Answer 1 and 3.arrow_forward
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