Essentials Of Materials Science And Engineering
Essentials Of Materials Science And Engineering
4th Edition
ISBN: 9781337670845
Author: ASKELAND
Publisher: Cengage
Question
Book Icon
Chapter 13, Problem 13.39P
Interpretation Introduction

(a)

Interpretation:

The maximum diameter of bar 1050 that will produce a minimum hardness of  HRC40 should be determined.

Concept introduction:

Hardness is the property of material which provides resistance to permanent deformation such as wear, abrasion, and scratch. It helps in define the characteristics of the material and its function ability according to its requirement.

Jominy test is test used for comparing the hardness of steel. The graph for Joimy distance is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  1

Expert Solution
Check Mark

Answer to Problem 13.39P

The required value of maximum diameter of bar 1050 that will produce a minimum hardness of HRC40 is 1.3inch.

Explanation of Solution

Given information:

Agitated water is used for quenching of steel.

Minimum hardness of HRC40 is considered.

Calculation of Jominy thickness using the given data of steel 1050 at HRC 40:

Using the graph of Jominy distance with Rockwell hardness test, drawing the tie lines for determining the value of Jominy thickness:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  2

Thus, the Jominy distance for 1050:HRC 40 is 316ofaninch.

Using Jominy distance for calculating the value of maximum diameter using graph,

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  3

Using the Jominy distance of 316ofaninch, drawing a line for calculating the maximum diameter.

Maximum diameter of 1050:HRC 40 is 1.3inch.

Interpretation Introduction

(b)

Interpretation:

The maximum diameter of bar 1080 that will produce a minimum hardness  HRC40 should be determined.

Concept introduction:

Hardness is the property of material which provides resistance to permanent deformation such as wear, abrasion, and scratch. It helps in define the characteristics of the material and its function ability according to its requirement.

Jominy test is test used for comparing the hardness of steel. The graph for Joimy distance is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  4

Expert Solution
Check Mark

Answer to Problem 13.39P

The required value of maximum diameter of bar 1080 that will produce a minimum hardness of HRC40 is 1.9inch.

Explanation of Solution

Calculation of Jominy thickness using the given data of steel 1080 at HRC 40:

Using the graph of Jominy distance with Rockwell hardness test, drawing the tie lines for determining the value of Jominy thickness:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  5

Thus, the Jominy distance for 1080:HRC 40 is 1016ofaninch.

Using Jominy distance for calculating the value of maximum diameter using graph,

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  6

Using the Jominy distance of 1016ofaninch, drawing a line for calculating the maximum diameter.

Maximum diameter of 1080:HRC 40 is 1.9inch.

Interpretation Introduction

(c)

Interpretation:

The maximum diameter of bar 4320 that will produce a minimum hardness  HRC40 should be determined.

Concept introduction:

Hardness is the property of material which provides resistance to permanent deformation such as wear, abrasion, and scratch. It helps in define the characteristics of the material and its function ability according to its requirement.

Jominy test is test used for comparing the hardness of steel. The graph for Joimy distance is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  7

Expert Solution
Check Mark

Answer to Problem 13.39P

The required value of maximum diameter of bar 4320 that will produce a minimum hardness of HRC40 is 1.9inch.

Explanation of Solution

Calculation of Jominy thickness using the given data of steel 4320 at HRC 40:

Using the graph of Jominy distance with Rockwell hardness test, drawing the tie lines for determining the value of Jominy thickness:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  8

Thus, the Jominy distance for 4320:HRC 40 is 516ofaninch.

Using Jominy distance for calculating the value of maximum diameter using graph,

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  9

Using the Jominy distance of 516ofaninch, drawing a line for calculating the maximum diameter.

Maximum diameter of 4320:HRC 40 is 1.9inch.

Interpretation Introduction

(d)

Interpretation:

The maximum diameter of bar 8640 that will produce a minimum hardness  HRC40 should be determined.

Concept introduction:

Hardness is the property of material which provides resistance to permanent deformation such as wear, abrasion, and scratch. It helps in define the characteristics of the material and its function ability according to its requirement.

Jominy test is test used for comparing the hardness of steel. The graph for Joimy distance is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  10

Expert Solution
Check Mark

Answer to Problem 13.39P

The required value of maximum diameter of bar 8640 that will produce a minimum hardness of HRC40 is greater than 2.5inch.

Explanation of Solution

Calculation of Jominy thickness using the given data of steel 8640 at HRC 40:

Using the graph of Jominy distance with Rockwell hardness test, drawing the tie lines for determining the value of Jominy thickness:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  11

Thus, the Jominy distance for 8640:HRC 40 is 1916ofaninch.

Using Jominy distance for calculating the value of maximum diameter using graph,

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  12

Using the Jominy distance of 1916ofaninch, drawing a line for calculating the maximum diameter.

Maximum diameter of 8640:HRC 40 is greater than 2.5inch.

Interpretation Introduction

(e)

Interpretation:

The maximum diameter of bar 4340 that will produce a minimum hardness  HRC40 should be determined.

Concept introduction:

Hardness is the property of material which provides resistance to permanent deformation such as wear, abrasion, and scratch. It helps in define the characteristics of the material and its function ability according to its requirement.

Jominy test is test used for comparing the hardness of steel. The graph for Joimy distance is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  13

Expert Solution
Check Mark

Answer to Problem 13.39P

The required value of maximum diameter of bar 4340 that will produce a minimum hardness of HRC40 is greater than 2.5inch.

Explanation of Solution

Calculation of Jominy thickness using the given data of steel 4340 at HRC 40:

Using the graph of Jominy distance with Rockwell hardness test, drawing the tie lines for determining the value of Jominy thickness:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  14

Thus, the Jominy distance for 4340:HRC 40 is 2016ofaninch.

Using Jominy distance for calculating the value of maximum diameter using graph,

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.39P , additional homework tip  15

Using the Jominy distance of 2016ofaninch, drawing a line for calculating the maximum diameter.

Maximum diameter of 4340:HRC 40 is greater than 2.5inch.

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