EBK EXPLORING CHEMICAL ANALYSIS
EBK EXPLORING CHEMICAL ANALYSIS
5th Edition
ISBN: 8220101443908
Author: Harris
Publisher: MAC HIGHER
Question
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Chapter 13, Problem 13.1P

(a)

Interpretation Introduction

Interpretation:

Milliliters of 0.0500 M EDTA required to react with 50.0 mL of 0.0100 M Ca2+ have to be determined.

Concept Introduction:

EDTA or ethylenediaminetetraacetic acid is used for titration of majority of metals with help of formation of strong metal complexes in the ratio of 1:1. It is utilized to bind metals, most commonly used in industrial processes. It is also used for prevention of food oxidation and in environmental chemistry.

Formula to calculate molarity of solution is as follows:

  Molarity of solution(M)=Moles of soluteVolume (L) of solution        (1)

(a)

Expert Solution
Check Mark

Answer to Problem 13.1P

Volume of 0.0500 M EDTA required to react with 50.0 mL of 0.0100 M Ca2+ is 10 mL.

Explanation of Solution

Rearrange equation (1) for moles of solute.

  Moles of solute=[(Molarity of solution(M))(Volume (L) of solution)]        (2)

Substitute 0.0100 M for molarity of solution and 50.0 mL for volume of solution in equation (2) to calculate moles of Ca2+.

  Moles of Ca2+=(0.0100 M)(50.0 mL)(103 L1 mL)=0.0005 mol

Since EDTA always forms complexes with metals in ratio of 1:1, 0.0005 moles of Ca2+ will react with same number of moles of EDTA.

Rearrange equation (1) for volume of solution.

  Volume(L) of solution=Moles of soluteMolarity(M) of solution        (3)

Substitute 0.0005 mol for moles of solute and 0.0500 M for molarity of solution in equation (3) to calculate volume of EDTA solution.

  Volume of EDTA solution=(0.0005 mol0.0500 M)(103 mL1 L)=10 mL

Hence, required volume of EDTA solution is 10 mL.

(b)

Interpretation Introduction

Interpretation:

Milliliters of 0.0500 M EDTA required to react with 50.0 mL of 0.0100 M Al3+ have to be determined.

Concept Introduction:

EDTA or ethylenediaminetetraacetic acid is used for titration of majority of metals with help of formation of strong metal complexes in the ratio of 1:1. It is utilized to bind metals, most commonly used in industrial processes. It is also used for prevention of food oxidation and in environmental chemistry.

Formula to calculate molarity of solution is as follows:

  Molarity of solution(M)=Moles of soluteVolume (L) of solution        (1)

(b)

Expert Solution
Check Mark

Answer to Problem 13.1P

Volume of 0.0500 M EDTA required to react with 50.0 mL of 0.0100 M Al3+ is 10 mL.

Explanation of Solution

Rearrange equation (1) for moles of solute.

  Moles of solute=[(Molarity of solution(M))(Volume (L) of solution)]        (2)

Substitute 0.0100 M for molarity of solution and 50.0 mL for volume of solution in equation (2) to calculate moles of Al3+.

  Moles of Al3+=(0.0100 M)(50.0 mL)(103 L1 mL)=0.0005 mol

Since EDTA always forms complexes with metals in ratio of 1:1, 0.0005 moles of Al3+ will react with same number of moles of EDTA.

Rearrange equation (1) for volume of solution.

  Volume(L) of solution=Moles of soluteMolarity(M) of solution        (3)

Substitute 0.0005 mol for moles of solute and 0.0500 M for molarity of solution in equation (3) to calculate volume of EDTA solution.

  Volume of EDTA solution=(0.0005 mol0.0500 M)(103 mL1 L)=10 mL

Hence, required volume of EDTA solution is 10 mL.

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