Explanation Given Information: The equations with solutions are x 4 − 4 x = 0 ; x = 4 or x = − 4 , 5 x = 6 x − 1 3 ; x = 3 and t + 2 5 − t − 2 4 = 1 ; t = − 2 Explanation: Consider the first equation with solutions as below: x 4 − 4 x = 0 ; x = 4 or x = − 4 Rewrite the equation in two equations and mark as below: Y 1 = ( X/4 ) − ( 4 / X ) Y 2 = 0 Use Ti-83 calculator to enter the above equations: Step 1: Press ON key then press [Y=] key and enter the equations as below: Y 1 = ( X/4 ) − ( 4 / X ) Y 2 = 0 Step 2: Press the 2 nd + WINDOW key and set up any desired values as below, Step 3: Press the 2 nd + GRAPH key and enter the value x = 4 or x = − 4 to get the value. Since, the values of Y 1 and Y 2 in the table are all equal at x = 4 and x = − 4 , that means x = 4 and x = − 4 is the solution for x 4 − 4 x = 0 . Consider the second equation with solutions as below: 5 x = 6 x − 1 3 ; x = 3 Use Ti-83 calculator to enter the above equations: Step 1: Press ON key then press [Y=] key and enter the equations as below: Y 1 = ( 5 / X ) Y 2 = ( 6 / X ) − ( 1 / 3 ) Step 2: Press the 2 nd + WINDOW key and set up any desired values as below, Step 3: Press the 2 nd + GRAPH key and enter the value x = 3 to get the value table

9th Edition

ISBN: 9780321997173

Author: Marvin L. Bittinger, Judith A. Beecher

Publisher: PEARSON

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Chapter 12.7, Problem 58ES

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Whether the solution of the equations is correct or not by the use of the graphing calculator. The equations with solutions are x4−4x=0;x=4 or x=−4,5x=6x−13;x=3, and t+25−t−24=1;t=−2.

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Chapter 12.7, Problem 57ES

Chapter 12.8, Problem 1SR

Chapter 12 Solutions

Developmental Mathematics (9th Edition)

Ch. 12.1 - Objective 11.3a: Factor trinomials of the type...Ch. 12.1 - Prob. 2SR Ch. 12.1 - Prob. 1DE Ch. 12.1 - Prob. 2DE Ch. 12.1 - Prob. 3DE Ch. 12.1 - Prob. 4DE Ch. 12.1 - Prob. 5DE Ch. 12.1 - Prob. 6DE Ch. 12.1 - Prob. 7DE Ch. 12.1 - Prob. 8DE

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Whether the solution of the equations is correct or not by the use of the graphing calculator. The equations with solutions are x 4 − 4 x = 0 ; x = 4 or x = − 4 , 5 x = 6 x − 1 3 ; x = 3 , and t + 2 5 − t − 2 4 = 1 ; t = − 2 .

Solution Summary: The author explains how the graphing calculator determines whether the solution of the equations is correct or not.

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Whether the solution of the equations is correct or not by the use of the graphing calculator. The equations with solutions are x4−4x=0;x=4 or x=−4,5x=6x−13;x=3, and t+25−t−24=1;t=−2.

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Chapter 12 Solutions