Chapter 12.7, Problem 17P

You choose a marble at random from a bag containing 2 red marbles, 4 green marbles, and 3 blue marbles. Find the odds.

odds against blue

To determine

Find the odds against blue.

Answer to Problem 17P

  $\frac{2}{1}$ = 2 : 1

Explanation of Solution

Given:

You choose a marble at random from a bag containing 2 red marbles, 4 green marbles, and 3 blue marbles.

Formula Used :

  $\text{odds against E = }\frac{\text{number of failures}}{\text{number of successes of E}}$

Calculation:

Number of success for blue = 3

Number of failures = 2 + 4 = 6

  $\text{odds against blue =}\frac{\text{number of failures}}{\text{number of successes}}=\frac{6}{3}=\frac{2}{1}$ = 2 : 1