Chapter 12.3, Problem 24HP

To determine

To find: Area of given Flower

Answer to Problem 24HP

  $\text{58}{\text{.42in}}^{\text{2}}$

Explanation of Solution

Given:

We know that,

  $Radiusofcircle=2in,heightof\text{ triangle=2}\text{.7in}$

Formula used:

  $\text{area of triangle=}\frac{\text{1}}{\text{2}}{\text{×b×h,area of circle=πr}}^{\text{2}}$

Calculation:

  $\begin{array}{l}\text{area of pentagon=}\frac{\text{1}}{\text{2}}\text{×4×2}\text{.7×5}\\ {\text{=27in}}^{\text{2}}\\ \text{Total area of semi circle=}\frac{\text{1}}{\text{2}}{\text{×5×π×r}}^{\text{2}}\\ \text{=}\frac{\text{1}}{\text{2}}\text{×5×}\frac{\text{22}}{\text{7}}{\text{×2}}^{\text{2}}\\ \text{=}\frac{\text{220}}{\text{7}}{\text{in}}^{\text{2}}\\ \text{area of flower=27+}\frac{\text{220}}{\text{7}}\text{=58}{\text{.42in}}^{\text{2}}\end{array}$