The speed of water flowing out of the pipe.
Answer to Problem 8TP
Explanation of Solution
Given:
Diameter of pipe =3.5cm
Force=
Rate of flowing water = 2.5m/s
Pumped water level = 21m
Formula used:
According to the Bernoulli's principle,
Where
Calculation:
The left hand side of the equation is evaluated initially.
The cross-sectional area of the pipe is calculated as
Where, A -Area of the pipe cross section, d -Diameter of the pipe cross section.
Substitute the diameter value 3.5 cm in the above equation.
The plunger pressure of fluid due to force is calculated as
Where, F -plunger force, P -plunger pressure, A -area of cross-section of pipe
Substitute the above found values in equation
The lower end water is assumed to be zero.Hence
Substitute the above found values in equation:
Now the right hand side of the equation is evaluated.
The upper end atmospheric pressure is 1 atm
Hence,
Substitute the values
Since both sides of the equation is equal, therefore
Take square root on both sides
Conclusion:
Hence, the speed of water flows out pipe is
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Chapter 12 Solutions
COLLEGE PHYSICS
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