Traffic and Highway Engineering
5th Edition
ISBN: 9781305156241
Author: Garber, Nicholas J.
Publisher: Cengage Learning
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Question
Chapter 12, Problem 8P
To determine
The trip distribution calculation using the gravity model for two iterations.
Expert Solution & Answer
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Students have asked these similar questions
A study area consists of three zones. The data have been determined as shown in the following
tables.
Zone Productions and Attractions
Zone
1
2
3
Total
Trip Productions
140
330
280
750
Trip Attractions
300
270
180
750
Travel Time between zones (min)
Zone
1
3
1
5
3
2
3
3
5
Travel Time versus Friction Factor
Time (min)
F
1
82
2
52
3
50
4
41
5
39
6
26
7
20
8
12
Determine the number of trips between each zone using the gravity model. Show all steps in the
calculation of friction factors and iterations for balancing attractions and productions.
6.
A Study area with four transportation analysis zones has the following information:
Table 3: Trip productions and attractions for a four-zone study area and travel time between zones.
Travel Time, (t) (min)
Zone
Trip productions
Trip
I
220
2
240
3
330
4
230
attractions
350
270
210
190
Table 4: Travel time versus friction factor.
Time (min)
2
Friction Factor
61
1
78
from zone 1
4
9
10
6
3
47
4
37
from zone 2
5
29
5
6
7
5
6
22
from zone 3
7
17
6
8
7
6
8
14
from zone 4
9
10
8
9
11
7
10
8
Using a gravity model, determine the number of trips from zone to zone through two iterations. (Assume that the
socioeconomic adjustment factor is 1.0).
A town in Canada has been divided into three traffic zones. An origin-destination survey was conducted earlier this yearand yielded the number of trips between each zone as shown in the table below. Travel times between zones were alsodetermined. Provide a trip distribution calculation using the gravity model for two iterations. Assume Kij= 1.
Chapter 12 Solutions
Traffic and Highway Engineering
Ch. 12 - Prob. 1PCh. 12 - Prob. 2PCh. 12 - Prob. 3PCh. 12 - Prob. 4PCh. 12 - Prob. 5PCh. 12 - Prob. 6PCh. 12 - Prob. 7PCh. 12 - Prob. 8PCh. 12 - Prob. 9PCh. 12 - Given a table with production and attraction data,...
Ch. 12 - Given a table with production and attraction data,...Ch. 12 - Prob. 12PCh. 12 - Prob. 13PCh. 12 - Prob. 14PCh. 12 - Prob. 15PCh. 12 - Prob. 16PCh. 12 - Prob. 17PCh. 12 - Prob. 18PCh. 12 - Prob. 19PCh. 12 - Prob. 20PCh. 12 - Prob. 21PCh. 12 - Prob. 22PCh. 12 - Prob. 23PCh. 12 - Prob. 24PCh. 12 - Prob. 25PCh. 12 - Prob. 26PCh. 12 - Prob. 27PCh. 12 - Prob. 28P
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- Determine the trip distribution matrix using "Gravity Model" of transport system with given the data: Trip Production of Zones 1, 2 and 3, correspondingly are 500, 600, and 800 tpd Trip Attraction of Zones 1, 2 and 3, correspondingly are 600, 700 and 600 tpdarrow_forward4. The present trip ends and travel time matrix between the zones are shown in Tables 6.75 and 6.76, respectively. Travel impendance factor between the zones may be assumed to be e-tij, The socio-economic adjustment factors between the zones may be assumed to one. Calculate the trip interchanges between the zones by using the gravity model. TABLE 6.75 Zones Trips produced Trips attracted 1 2500 3000 2 3300 4000 3 3200 2000 TABLE 6.76 1 2 3 1 15 20 2 15 10 3 20 10arrow_forwardA zone has been divided into four large districts (traffic zones). The following data has been collected for those districts. Provide a trip distribution calculation (single constrained) using the gravity model. Assume Kij = 1 (Check balancing of Tij = A after the first iteration) District 1 2 3 4 Travel Time Fij Productions 3400 6150 3900 2800 1 2.0 Attractions 2800 6500 2550 4400 4 1.6 6 1.0 1 4 11 15 10 9 10 0.9 0.86 Travel time (min) 2 3 11 15 6 6 6 6 9 11 11 12 0.82 0.80 4 10 9 11 4 15 20 0.68 0.49arrow_forward
- Q1. The following is the number of trips and the number of households by the number of persons per household and the level of household income in a given zone. Persons/hh 1 2 3 4 5 or above Low No. of hh 93 72 59 120 13 Persons/household 1 2 3 4 5 or more Trip No. 222 341 417 1010 107 Income Medium Low 120 100 90 150 30 No. of hh 149 138 125 109 37 Trip No. 616 853 1025 1186 457 The forecasted number of households in the study area for a target year is shown below. High Income Medium 280 220 190 180 60 No. of hh 96 27 33 40 33 Trip No. 360 205 381 471 423 High 130 40 50 70 60arrow_forwardMiami, Oklahoma has three transportation analysis zones, and origin-destination survey results. Using a spreadsheet, provide a trip distribution calculation using the gravity model. The following table shows the number of productions and attractions in each zone, as well as the socioeconomic adjustment factor.arrow_forwardQ1. Develop statistical model to predict number of trips using regression analysis technique. Number of workers (X) Number of trips(Y) 2 6 4 8 7 10 7 11arrow_forward
- A multiple regression analysis shows the following relationship for the number of trips per household. T = 0.82 + 1.3P + 2.1A Where T = number of trips per household per day P= number of persons per household A= number of autos per household If a particular TAZ contains 250 households with an average of 4 persons and 2 autos for each household, determine the average number of trips per day in that zonearrow_forwardThe following socioeconomic data have been collected for the Jeffersonville Transportation Study (JTS). Population = 72,173 Area = 70 square miles Registered Vehicles = 26,685 Single-family housing units = 15,675 Apartment units = 7567 Retail employment = 5502 Nonretail employment = 27,324 Student attendance = 28,551 by zone of attendance Average household income = $17,500 Total traffic zones = 129 The results of the cross-classification analysis are as follows. Total trips produced for study area = 282,150 trips/day Home-to-work trips 13% (36,680) Home-to-nonwork trips 62% (174,933) Non-home trips 25% (70,537) The attraction rates for the study area have been developed using the following assumptions. 100% of home-to-work trips go to employment locations. Home-to-nonwork trips are divided into the following types. Visit…arrow_forwardI 100 3 25 300 1 Current Year IV 50 75 25 200 Future Year T[I] T[I] 250 4 400 2 150 III = 300 = 1000 T [III] = 800 T [IV] = 300 Distribute the trips for inter zonal movement based on Uniform Growth Factor Method and Detroit Method. Compare the iteration number & give your conclusion.arrow_forward
- Question 3 a) Explain the 'gravity model' adopted in trip distribution, and how that can be used to link land and transport planning. 100 50 50 b) Given an initial trip matrix t = with two origins and three 200 100 200 destinations. We also have a target trip generation from the two origins: 300 a = 600 and the trip attraction to the three destinations: b = [400 200 300]. Perform two iterations of Furness Procedure in order to adjust the trip matrix T such that the trip generation and attraction therein will match those specified.arrow_forwardUse the singly constraint growth factor model to calculate the projected trips in Cell (1,2) for the following observed trip table and forecast trip ends. Zone 1 0 Zone 2 200 Zone 3 30 O 54 O 36 O Zone 1 Zone 2 Zone 3 O 20 90 20 40 30 40 Forecast Trip Ends 90 90 140arrow_forwardIn a survey in the base year, the trip attraction, number of employees and shopping area in the zones are found as follows: Zone 1 2 3 4 5 6 7 8 9 10 Trip attraction (Trips/day) 34,000 33,000 37,000 9,000 19,000 20,000 50,000 22,000 21,000 5,000 Number of employees (persons) 2000 1500 3000 500 1000 1000 3200 1800 1600 200 Shopping area (m²) 250,000 350,000 150,000 80,000 160,000 180,000 350,000 60,000 100,000 50,000 Prepare a excel worksheet to calculate the generation model by regression analysis.arrow_forward
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