Chapter 12, Problem 63P

To determine

To show: The angle $\theta$ is formed by a sonic boom with the path of a supersonic object is given by $\sin \theta =\frac{v}{C}=\frac{1}{M}$ .

Explanation of Solution

Introduction:

If the source exceeds the speed of sound, then no sound that can be received by an observer until the source has passed.

Naturally, the superposition creates a disturbance known as a shock wave. Constructive interference is the phenomenon of a sound is created by an object that is moving very fast than the sound.

The most destructive interference is found inside the cone, so the intensity of sound is high on the shock wave.

When the sound barrier is broken by the plane breaks, a sonic boom occurs and it accelerates to a speed that is higher than the sound’s speed.

  $\sin \theta =\frac{v}{C}=\frac{1}{M}$

Conclusion:

Therefore, the angle ? is formed by a sonic boom with a supersonic object path is $\sin \theta =\frac{v}{C}=\frac{1}{M}$ .