ORGANIC CHEMISTRY (LL) >CUSTOM PACKAGE<
ORGANIC CHEMISTRY (LL) >CUSTOM PACKAGE<
4th Edition
ISBN: 9781119838791
Author: Klein
Publisher: WILEY
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Chapter 12, Problem 50PP
Interpretation Introduction

Interpretation: The alkyne has been oxidized or reduced in the given reaction.

Concept introduction: Oxidation takes place because of the removal of electrons whereas reduction takes place as a result of the addition of electrons. The oxidized component becomes positively charged and the reduced component becomes negatively charged.

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In the following reaction, determine whether the alkyne has been oxidized, reduced, or neither. (Hint: First look at each carbon atom separately and then look at the net change for the alkyne as a whole.) Try to determine the answer without calculating oxidation states and then use the calculations to see if your intuition was correct. H2SO4, H2O H9SO4 The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has also been oxidized. Overall, the alkyne has been oxidized. The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has also been reduced. Overall, the alkyne has been reduced. The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has been reduced. Overall, the alkyne does not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized. The first carbon…
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