Bundle: An Introduction to Physical Science, 14th Loose-leaf Version + WebAssign Printed Access Card, Single Term. Shipman/Wilson/Higgins/Torres
Bundle: An Introduction to Physical Science, 14th Loose-leaf Version + WebAssign Printed Access Card, Single Term. Shipman/Wilson/Higgins/Torres
14th Edition
ISBN: 9781305719057
Author: James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher: Cengage Learning
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Chapter 12, Problem 4E

Calculate (to the nearest 0.1 u) the formula mass of these compounds:

  1. (a) glucose, C6H12O6
  2. (b) sucrose, C12H22O11
  3. (c) azithromycin, C38H72N2O12

(a)

Expert Solution
Check Mark
To determine
The formula mass of glucose (C6H12O6) .

Answer to Problem 4E

The formula mass of glucose (C6H12O6) is 180.0 u .

Explanation of Solution

Formula mass of any compound is given as the sum of the atomic masses of the constituent atoms given in the chemical formula of a substance. Formula mass and atomic mass are abbreviated as FM and AM respectively.

The formula mass of glucose (C6H12O6) is given as,

FM of (C6H12O6) = [(6×AM of carbon atom)+(12×AM of hydrogen atom)+(6×AM of oxygen atom)] (1)

Atomic mass (AM) of carbon atom is 12.0 u .

Atomic mass (AM) of hydrogen atom is 1.0 u .

Atomic mass (AM) of oxygen atom is 16.0 u .

Substitute 12.0 u for AM of carbon atom , 1.0 u for AM of hydrogen atom and 16.0 u for AM of oxygen atom in equation (1).

FM of C6H12O6 = (6×12.0 u)+(12×1.0 u)+(6×16.0 u)=180.0 u

Conclusion:

Therefore, the formula mass of glucose (C6H12O6) is 180.0 u .

(b)

Expert Solution
Check Mark
To determine
The formula mass of sucrose (C12H22O11) .

Answer to Problem 4E

The formula mass of sucrose (C12H22O11) is 342.0 u .

Explanation of Solution

Formula mass of any compound is given as the sum of the atomic masses of the constituent atoms given in the chemical formula of a substance. Formula mass and atomic mass are abbreviated as FM and AM respectively.

The formula mass of sucrose (C12H22O11) is given as,

FM of (C12H22O11) =[(12×AM of carbon atom)+(22×AM of hydrogen atom)+(11×AM of oxygen atom)] (2)

Atomic mass (AM) of carbon atom is 12.0 u .

Atomic mass (AM) of hydrogen atom is 1.0 u .

Atomic mass (AM) of oxygen atom is 16.0 u .

Substitute 12.0 u for AM of carbon atom , 1.0 u for AM of hydrogen atom and 16.0 u for AM of oxygen atom in equation (2).

FM of C12H22O11 = (12×12.0 u)+(22×1.0 u)+(11×16.0 u)=342.0 u

Conclusion:

Therefore, the formula mass of sucrose (C12H22O11) is 342.0 u .

(c)

Expert Solution
Check Mark
To determine
The formula mass of azithromycin (C38H72N2O12) .

Answer to Problem 4E

The formula mass of azithromycin (C38H72N2O12) is 748.0 u .

Explanation of Solution

Formula mass of any compound is given as the sum of the atomic masses of the constituent atoms given in the chemical formula of a substance. Formula mass and atomic mass are abbreviated as FM and AM respectively.

The formula mass of azithromycin (C38H72N2O12) is given as,

FM of (C38H72N2O12) =[(38×AM of carbon atom)+(72×AM of hydrogen atom)+(2×AM of nitrogen atom)+(12×AM of oxygen atom)] (3)

Atomic mass (AM) of carbon atom is 12.0 u .

Atomic mass (AM) of hydrogen atom is 1.0 u .

Atomic mass (AM) of oxygen atom is 16.0 u .

Atomic mass (AM) of nitrogen atom is 14.0 u .

Substitute 12.0 u for AM of carbon atom , 1.0 u for AM of hydrogen atom , 14.0 u for AM of nitrogen atom and 16.0 u for AM of oxygen atom in equation (3).

FM of C38H72N2O12 = (38×12.0 u)+(72×1.0 u)+(2×14.0 u)+(12×16.0 u)=748.0 u

Conclusion:

Therefore, the formula mass of azithromycin (C38H72N2O12) is 748.0 u .

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Chapter 12 Solutions

Bundle: An Introduction to Physical Science, 14th Loose-leaf Version + WebAssign Printed Access Card, Single Term. Shipman/Wilson/Higgins/Torres

Ch. 12.4 - Prob. 2PQCh. 12.4 - Prob. 12.4CECh. 12.4 - Prob. 12.5CECh. 12.5 - Prob. 1PQCh. 12.5 - Prob. 2PQCh. 12.5 - Prob. 12.6CECh. 12.6 - Is PCl3 ionic or covalent in bonding? What about...Ch. 12.6 - Prob. 12.8CECh. 12.6 - Boron trifluoride, BF3, is an exception to the...Ch. 12.6 - Prob. 1PQCh. 12.6 - Prob. 2PQCh. 12 - Prob. AMCh. 12 - Prob. BMCh. 12 - Prob. CMCh. 12 - Prob. DMCh. 12 - Prob. EMCh. 12 - Prob. FMCh. 12 - Prob. GMCh. 12 - Prob. HMCh. 12 - Prob. IMCh. 12 - Prob. JMCh. 12 - Prob. KMCh. 12 - Prob. LMCh. 12 - Prob. MMCh. 12 - Prob. NMCh. 12 - Prob. OMCh. 12 - Prob. PMCh. 12 - Prob. QMCh. 12 - Prob. RMCh. 12 - Prob. SMCh. 12 - Prob. 1MCCh. 12 - Prob. 2MCCh. 12 - Prob. 3MCCh. 12 - Prob. 4MCCh. 12 - Prob. 5MCCh. 12 - Prob. 6MCCh. 12 - Prob. 7MCCh. 12 - Prob. 8MCCh. 12 - Prob. 9MCCh. 12 - Prob. 10MCCh. 12 - Sodium reacts with a certain element to form a...Ch. 12 - Prob. 12MCCh. 12 - Prob. 13MCCh. 12 - Carbon is a Group 4A element. How many covalent...Ch. 12 - How many shared pairs of electrons are in an...Ch. 12 - Prob. 16MCCh. 12 - Prob. 17MCCh. 12 - Prob. 18MCCh. 12 - Prob. 1FIBCh. 12 - Prob. 2FIBCh. 12 - Prob. 3FIBCh. 12 - Prob. 4FIBCh. 12 - Prob. 5FIBCh. 12 - Prob. 6FIBCh. 12 - Prob. 7FIBCh. 12 - The formula of an ionic compound of a Group 1A...Ch. 12 - Prob. 9FIBCh. 12 - Prob. 10FIBCh. 12 - Prob. 11FIBCh. 12 - Prob. 12FIBCh. 12 - Prob. 1SACh. 12 - Prob. 2SACh. 12 - Prob. 3SACh. 12 - Prob. 4SACh. 12 - Prob. 5SACh. 12 - Prob. 6SACh. 12 - Prob. 7SACh. 12 - Prob. 8SACh. 12 - Prob. 9SACh. 12 - Prob. 10SACh. 12 - Prob. 11SACh. 12 - Prob. 12SACh. 12 - Prob. 13SACh. 12 - Prob. 14SACh. 12 - Prob. 15SACh. 12 - Prob. 16SACh. 12 - Prob. 17SACh. 12 - Prob. 18SACh. 12 - Prob. 19SACh. 12 - Prob. 20SACh. 12 - Prob. 21SACh. 12 - Prob. 22SACh. 12 - Prob. 23SACh. 12 - Prob. 24SACh. 12 - Prob. 25SACh. 12 - A covalent bond in which the electron pair is...Ch. 12 - Could a molecule composed of two atoms joined by a...Ch. 12 - Explain how a polyatomic ion such as carbonate...Ch. 12 - Prob. 29SACh. 12 - Prob. 30SACh. 12 - Prob. 31SACh. 12 - State the short general principle of solubility,...Ch. 12 - Prob. 33SACh. 12 - Prob. 1VCCh. 12 - You decide to have hot dogs for dinner. In the...Ch. 12 - Why cant we destroy bothersome pollutants by just...Ch. 12 - Prob. 3AYKCh. 12 - When you use a bottle of vinegar-and-oil salad...Ch. 12 - Prob. 5AYKCh. 12 - Prob. 6AYKCh. 12 - Prob. 1ECh. 12 - An antacid tablet weighing 0.942 g contained...Ch. 12 - Calculate (to the nearest 0.1 u) the formula mass...Ch. 12 - Calculate (to the nearest 0.1 u) the formula mass...Ch. 12 - Find the percentage by mass of Cl in MgCl2 if it...Ch. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Prob. 11ECh. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Write the Lewis symbols and structures that show...Ch. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Referring only to a periodic table, give the...Ch. 12 - Referring only to a periodic table, give the...Ch. 12 - Prob. 23ECh. 12 - Draw the Lewis structure for formaldehyde, H2CO, a...Ch. 12 - Prob. 25ECh. 12 - Prob. 26ECh. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Use arrows to show the polarity of each bond in...Ch. 12 - Use arrows to show the polarity of each bond in...Ch. 12 - Prob. 31ECh. 12 - Prob. 32E
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