Essential Statistics for the Behavioral Sciences
2nd Edition
ISBN: 9781506386300
Author: Gregory J. Privitera
Publisher: SAGE Publications, Inc
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Chapter 12, Problem 3FP
a.
To determine
To explain: The term cell.
b.
To determine
To explain: The term main effect.
c.
To determine
To explain: The term interaction.
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a.State the predictors available in this model.
The titanium content in an aircraft-grade alloy is an important determinant of strength. A
sample of 20 test coupons reveals the following titanium content (in percent):
8.32, 8.05, 8.93, 8.65, 8.25, 8.46, 8.52, 8.35, 8.36, 8.41, 8.42, 8.30, 8.71, 8.75, 8.60, 8.83, 8.50,
8.38, 8.29, 8.46. The median titanium content should be 8.5%.
Use the sign test with a = 0.05 to investigate this hypothesis. Match the answers.
Parameter of Interest:
a.r- = 12
v Null and Alternative Hypothesis:
b.r = min (R+,R-)
c.r sr.
Test Statistic:
d.
Reject the null hypothesis if.
e. Η0 μ=8.5
H;u#8.5
Conclusion:
f. Mean of the Titanium content
g. Median Titanium content
h. Η: μ 8.5
H:ñ + 8.5
i. Fail to reject the null hypothesis. There is not enough evidence to
conclude that the median of the titanium content differs from 8.5%.
j. Reject the null hypothesis. The median of the titanium content differs
from 8.5%.
The titanium content in an aircraft-grade alloy is an important determinant of strength. A
sample of 20 test coupons reveals the following titanium content (in percent):
8.32, 8.05, 8.93, 8.65, 8.25, 8.46, 8.52, 8.35, 8.36, 8.41, 8.42, 8.30, 8.71, 8.75, 8.60, 8.83, 8.50,
8.38, 8.29, 8.46. The median titanium content should be 8.5%.
Use the sign test with a = 0.05 to investigate this hypothesis. Match the answers.
Parameter of Interest:
a. Hi i =8.5
Null and Alternative Hypothesis:
Hiñ ±8.5
Test Statistic:
b. H H=8.5
H;u #8.5
v Reject the null hypothesis if.
Conclusion:
C.r- = 12
d. H; u =8.5
H:ã>8.5
e. Median Titanium content
f. Fail to reject the null hypothesis. There is not enough evidence to
conclude that the median of the titanium content differs from 8.5%.
h.r = min (R*,R-)
i. Mean of the Titanium content
i. Reject the null hypothesis. The median of the titanium content differs from
8.5%.
Chapter 12 Solutions
Essential Statistics for the Behavioral Sciences
Ch. 12 - Prob. 1FPCh. 12 - Prob. 2FPCh. 12 - Prob. 3FPCh. 12 - Prob. 4FPCh. 12 - Prob. 5FPCh. 12 - Prob. 6FPCh. 12 - Prob. 7FPCh. 12 - Prob. 8FPCh. 12 - Prob. 9FPCh. 12 - Prob. 10FP
Ch. 12 - Prob. 11FPCh. 12 - Prob. 12FPCh. 12 - Prob. 13CAPCh. 12 - Prob. 14CAPCh. 12 - Prob. 15CAPCh. 12 - Prob. 16CAPCh. 12 - Prob. 17CAPCh. 12 - Prob. 18CAPCh. 12 - Prob. 19CAPCh. 12 - Prob. 20CAPCh. 12 - Prob. 21CAPCh. 12 - Prob. 22CAPCh. 12 - Prob. 23CAPCh. 12 - Prob. 24CAPCh. 12 - Prob. 25CAPCh. 12 - Prob. 26CAPCh. 12 - Prob. 27CAPCh. 12 - Prob. 28CAPCh. 12 - Prob. 29PRCh. 12 - Prob. 30PRCh. 12 - Prob. 31PRCh. 12 - Prob. 32PR
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