Output of the code: The given code is as follows: #main function def main(): #initialize the variable num as 0 num = 0 #call show_me function with argument num show_me(num) #function definition for show_me function def show_me(arg): #Display the given arg print(arg) #check if the arg is less than 10 if arg 10: '''if arg is less than 10, then it calls show_me function with arg is incremented with 1''' show_me(arg + 1) #call main function main() If the above code is executed, it produces the syntax error on the “if” statement that is highlighted on the code. Syntax error: An error that occurs on the source code of a program is referred as “syntax error” because the computer programs strictly follow the syntax rules; if the code fails to prove its programming language syntax format, then the compiler throws an error.

Question

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Answer 1

Question

Chapter 12, Problem 2AW

Program Plan Intro

Output of the code:

The given code is as follows:

#main function

def main():

  #initialize the variable num as 0

  num = 0

  #call show_me function with argument num

  show_me(num)

#function definition for show_me function

def show_me(arg):

  #Display the given arg

  print(arg)

  #check if the arg is less than 10

  if arg 10:

         '''if arg is less than 10, then it calls show_me function

         with arg is incremented with 1'''

         show_me(arg + 1)

#call main function

main()

If the above code is executed, it produces the syntax error on the “if” statement that is highlighted on the code.

Syntax error:

An error that occurs on the source code of a program is referred as “syntax error” because the computer programs strictly follow the syntax rules; if the code fails to prove its programming language syntax format, then the compiler throws an error.

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#include void main () { int a=5,b=10,c=1; if (a && b>c) { printf("cquestionbank"); } else{ break; } }

Answer 2

Question

Chapter 12, Problem 2AW

Program Plan Intro

Output of the code:

The given code is as follows:

#main function

def main():

  #initialize the variable num as 0

  num = 0

  #call show_me function with argument num

  show_me(num)

#function definition for show_me function

def show_me(arg):

  #Display the given arg

  print(arg)

  #check if the arg is less than 10

  if arg 10:

         '''if arg is less than 10, then it calls show_me function

         with arg is incremented with 1'''

         show_me(arg + 1)

#call main function

main()

If the above code is executed, it produces the syntax error on the “if” statement that is highlighted on the code.

Syntax error:

An error that occurs on the source code of a program is referred as “syntax error” because the computer programs strictly follow the syntax rules; if the code fails to prove its programming language syntax format, then the compiler throws an error.

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Answer 3

Question

Chapter 12, Problem 2AW

Program Plan Intro

Output of the code:

The given code is as follows:

#main function

def main():

  #initialize the variable num as 0

  num = 0

  #call show_me function with argument num

  show_me(num)

#function definition for show_me function

def show_me(arg):

  #Display the given arg

  print(arg)

  #check if the arg is less than 10

  if arg 10:

         '''if arg is less than 10, then it calls show_me function

         with arg is incremented with 1'''

         show_me(arg + 1)

#call main function

main()

If the above code is executed, it produces the syntax error on the “if” statement that is highlighted on the code.

Syntax error:

An error that occurs on the source code of a program is referred as “syntax error” because the computer programs strictly follow the syntax rules; if the code fails to prove its programming language syntax format, then the compiler throws an error.

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Answer 4

Question

Chapter 12, Problem 2AW

Program Plan Intro

Output of the code:

The given code is as follows:

#main function

def main():

  #initialize the variable num as 0

  num = 0

  #call show_me function with argument num

  show_me(num)

#function definition for show_me function

def show_me(arg):

  #Display the given arg

  print(arg)

  #check if the arg is less than 10

  if arg 10:

         '''if arg is less than 10, then it calls show_me function

         with arg is incremented with 1'''

         show_me(arg + 1)

#call main function

main()

If the above code is executed, it produces the syntax error on the “if” statement that is highlighted on the code.

Syntax error:

An error that occurs on the source code of a program is referred as “syntax error” because the computer programs strictly follow the syntax rules; if the code fails to prove its programming language syntax format, then the compiler throws an error.

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Answer 5

Chapter 12, Problem 2AW

Program Plan Intro

Output of the code:

The given code is as follows:

#main function

def main():

  #initialize the variable num as 0

  num = 0

  #call show_me function with argument num

  show_me(num)

#function definition for show_me function

def show_me(arg):

  #Display the given arg

  print(arg)

  #check if the arg is less than 10

  if arg 10:

         '''if arg is less than 10, then it calls show_me function

         with arg is incremented with 1'''

         show_me(arg + 1)

#call main function

main()

If the above code is executed, it produces the syntax error on the “if” statement that is highlighted on the code.

Syntax error:

An error that occurs on the source code of a program is referred as “syntax error” because the computer programs strictly follow the syntax rules; if the code fails to prove its programming language syntax format, then the compiler throws an error.

Answer 6

Chapter 12, Problem 2AW

Program Plan Intro

Output of the code:

The given code is as follows:

#main function

def main():

  #initialize the variable num as 0

  num = 0

  #call show_me function with argument num

  show_me(num)

#function definition for show_me function

def show_me(arg):

  #Display the given arg

  print(arg)

  #check if the arg is less than 10

  if arg 10:

         '''if arg is less than 10, then it calls show_me function

         with arg is incremented with 1'''

         show_me(arg + 1)

#call main function

main()

If the above code is executed, it produces the syntax error on the “if” statement that is highlighted on the code.

Syntax error:

An error that occurs on the source code of a program is referred as “syntax error” because the computer programs strictly follow the syntax rules; if the code fails to prove its programming language syntax format, then the compiler throws an error.

Answer 7

Chapter 12, Problem 2AW

Program Plan Intro

Output of the code:

The given code is as follows:

#main function

def main():

  #initialize the variable num as 0

  num = 0

  #call show_me function with argument num

  show_me(num)

#function definition for show_me function

def show_me(arg):

  #Display the given arg

  print(arg)

  #check if the arg is less than 10

  if arg 10:

         '''if arg is less than 10, then it calls show_me function

         with arg is incremented with 1'''

         show_me(arg + 1)

#call main function

main()

If the above code is executed, it produces the syntax error on the “if” statement that is highlighted on the code.

Syntax error:

An error that occurs on the source code of a program is referred as “syntax error” because the computer programs strictly follow the syntax rules; if the code fails to prove its programming language syntax format, then the compiler throws an error.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 12.2 - It is said that a recursive algorithm has more...Ch. 12.2 - Prob. 2CP Ch. 12.2 - What is a recursive case?Ch. 12.2 - What causes a recursive algorithm to stop calling...Ch. 12.2 - What is direct recursion? What is indirect...Ch. 12 - Prob. 1MC Ch. 12 - A function is called once from a program's main...Ch. 12 - Prob. 3MC Ch. 12 - Prob. 4MC Ch. 12 - Prob. 5MC

Solution Summary: The author explains that the given code does not display the output since it contains the syntax error in the "if" condition statement.

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Chapter 12 Solutions