Fox And Mcdonald's Introduction To Fluid Mechanics
Fox And Mcdonald's Introduction To Fluid Mechanics
9th Edition
ISBN: 9781118921876
Author: Pritchard, Philip J.; Leylegian, John C.; Bhaskaran, Rajesh
Publisher: WILEY
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Chapter 12, Problem 1P

Air is expanded in a steady flow process through a turbine. Initial conditions are 1300°C and 2.0 MPa absolute. Final conditions are 500°C and atmospheric pressure. Show this process on a Ts diagram. Evaluate the changes in internal energy, enthalpy, and specific entropy for this process.

Expert Solution & Answer
Check Mark
To determine

The change in internal energy, enthalpy, specific entropy and show this process on a T-s diagram.

Explanation of Solution

Given:

Initial temperature (T1) is 1300°C.

Initial pressure (P1) is 2 MPa.

Final temperature (T2) is 500°C.

Final pressure (P2) is 1 atm.

Calculation:

Determine the change in internal energy.

  dU=U2U1=CvdT=Cv(T2T1)=0.718 kJ/kgK(773 K1573 K)=573.6 kJ/kg

Thus, the change in internal energy is 573.6 kJ/kg_.

Determine the change in enthalpy.

  dh=h2h1=CpdT=Cp(T2T1)=1.004 kJ/kgK(773 K1573 K)=803.2 kJ/kg

Thus, the change in enthalpy is 803.2 kJ/kg_.

Determine the change in specific entropy.

  ds=s2s1=Cpln(T2T1)Rln(P2P1)=1.004 kJ/kgK×ln(773 K1573 K)1.004 kJ/kgK×ln(101.325 kPa2000 kPa)=0.143 kJ/kgK

Thus, the change in specific entropy is 0.143 kJ/kgK_.

Draw the T-s diagram as in Figure (1).

Fox And Mcdonald's Introduction To Fluid Mechanics, Chapter 12, Problem 1P

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Chapter 12 Solutions

Fox And Mcdonald's Introduction To Fluid Mechanics

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