Chapter 12, Problem 14CCSR

Solution

To find: The value of $\log a^{2}b$ .

  $\log a^{2}b=1.9$

Given information:

Given, $\log a=0.6,\log b=0.7$ .

Calculation:

Simplifying the expression and plugging the values:

  $\begin{array}{l}\log a^{2}b=\log a^2+\log b\\ \log a^{2}b=2\log a+\log b\\ \log a^{2}b=2\left(0.6\right)+\left(0.7\right)\\ \log a^{2}b=1.2+0.7\\ \log a^{2}b=1.9\end{array}$

Conclusion:

  $\log a^{2}b=1.9$