Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 12, Problem 12.6P
To determine
Find the corrected penetration number
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The following are the results of a standard penetration test in sand. Determine the standard penetration
numbers, (N₁)60(CORR), at the various depths given. Note that the water table is at depth 5.0 m. Assume that
the average unit weight of sand is 15.5 kN/m³ above the water table and the saturated unit weight of sand
is 17.81 kN/m³, while the unit weight of water = 9.81 kN/m³.
Depth (m)
0.0
1.5
3.0
4.5
6.0
7.5
N60
0
10
15
19
24
28
Following are the results of a standard penetration test in sand. Determine the corrected
standard penetration number, (N1)60, at various depths. Note that the water table was not
observed within a depth of 10.5 m below the ground surface. Assume that the average
unit weight of sand is 17.3 kN/m3.
Depth (m) N60
1.5 8
3.0 7
4.6 12
6.0 14
7.5 13
b)
Table Q2 provides the result of a standard penetration test in the sandy soil. The water
table was not encountered during the test. Assume that the average unit weight of
sand is 17.3 kN/m³ and use Skempton's relationship provided, determine the corrected
standard penetration numbers, (N₁)eo at various depths given (CO1, PO2) (C3)
2
Skempton's equation: C = =
1+0.010!
Table Q2
Depth (m)
Noo
1.5
3.0
4.5
6.0
7.5
|4712419|
Chapter 12 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
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- 3. Following are the results of a standard penetration test in fine dry sand. N60 Depth (m) 1.5 7 13 3.0 18 4.5 22 6.0 7.5 24 For, the sand deposit, assume the mean grain size, D50, to be 0.26 mm and the unit weight of sand to be 15.5kN/m3. Estimate the variation of relative density with depth using the correlation developed by Cubrinovski and Ishihara. Assume pas100kN/m2. denined frictionarrow_forward= A standard penetration test is carried out in sand where the efficiency of the hammer n 50%. If the measured N-value at 7.5 m depth is 20, find Noo and (N₁)60. The unit weight of the sand is = 15 MR = 1 and 18.08 kN/m³. Assume ¹ = 0.95. If you know that: nsarrow_forwardThe following are the results of a standard penetration test in sand. Determine the corrected standard penetration numbers, (N,), at the various depths given. Note that the water table was not observed within a depth of 12 m below the ground surface. Assume that the average unit weight of sand is 15.5 kN/m³. Depth (m) 1.5 8 3 7 4.5 12 14 7.5 13arrow_forward
- In a deposit of normally consolidated dry sand a cone penetration test was conducted. Following are the result: Depth(m) Point resistance of cone, qc (MN/m²) 1.5 2.06 3.0 4.23 4.5 6.01 6.0 8.18 7.5 9.97 9.0 12.42 Assuming the dry unit weight of sand to be 16kN/m³, estimale the average peak friction angle, ф’, fo the sand. Use ф’=tan ¯1((0.38+0.27log(qc/ σ’o))arrow_forwardA standard penetration test is carried out in sand where the efficiency of the hammer nH =70%. If the measured N-value at 30 ft depth is 24, find N60 and (N1)60. The unit weight of the sand is 115.0 lb/ft3. Assume nB = nS = nR =1.arrow_forwardThe following table gives the variation of the field standard penetration number blows (N) in sand deposit: The ground water table is located at depth of 6m. The dry unit weight of sand from 0 to a depth of 6m is 18kN/m, and the saturated unit weight of sand for depth of 6m to 12m is 20.2kN/m'. Use the relationship to calculated correct (N) of standard penetration test against overburden effect. Depth (m) 1.5 No. of blows (N) 6. 3 8. 4.5 9 6. 8. 7.5 13 9. 14arrow_forward
- P-1 A soil profile is shown in Figure along with the standard penetration numbers in the clay layer. Use provided equations to Dry sand y = 16.5 kN/m³ 1.5 m Groundwater table Sand 1.5 m N60 Ysat = 19 kN/m³ determine the variation of 1.5 m • 8 Cu and OCR and preconsolidation pressure o', with depth. What is the average value of c, and OCR? Clay 1.5 m Ysat = 16.8 kN/m³ * A•8 1.5 m • 9 1.5 m 10 Sand 0.689 0.29N0.72 Pa Си N60 OCR = 0.193 o = 0.47NPa %3D %3D Shahid Chamran University of Abvaz 1 ר ר ררפarrow_forwardDetermine the relative density at each depth using attached equation. Assume moderately compressible sand and hence Qc = 1.arrow_forwardA soil profile is shown in Figure P3.2 along with the standard penetration numbers in the clay layer. Use Eqs. (3.8) and (3.9) to determine the variation of cu and OCR with depth. What is the average value of cu and OCR?arrow_forward
- The standard penetration test results of a sand deposit at a certain site are given below in tabular form. The groundwater table in located at a depth of 2 m below the ground surface. The dry and saturated unit weights of sand are 17 kN/m³ and 19.0 kN/m', respectively. For an expected 10.8 earthquake magnitude M = 6 and maximum acceleration amax = 0.1 g, will liquefaction occur? Depth (m) NF (blows/30 cm) 1.5 8 3.0 7 4.5 12 6.0 15 7.5 17 9.0 17arrow_forward3.8 Following are the standard penetration numbers deter- mined from a sandy soil in the field. (Note: The unit weight of soil for 0-6 m is 16.66 kv/m³; and is 18.5 kN/m³ from z = 6-12 m.) Depth (m) 3 4.5 6.0 7.5 9.0 10.5 12.0 Unit weight of soil (kN/m³) 16.66 16.66 16.66 18.5 18.5 18.5 18.5 N60 7 9 11 16 18 20 22 Using Eq. (3.30), determine the variation of the peak soil friction angle, '. Estimate an average value of o' for the design of a shallow foundation.arrow_forwardA soil profile is shown in Figure P3.3 along with the stan- dard penetration numbers in the clay layer. Use Eqs. (3.8b) and (3.9) to determine the variation of c, and OCR with depth. What is the average value of c, and OCR? Dry sand y = 16.5 kN/m² 1.5 m Groundwater table Sand 1.5 m Ysat = 19 kN/m³ N60 1.5 m • 8 Clay Ysat = 16.8 kN/m³ 1.5 m A • 8 1.5 m 9 1.5 m 10 Sandarrow_forward
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