What is the ∆H, ∆S, and ∆G when we isothermally mix 1.0 mol of toluene and 2.5 mol of benzene,assuming ideal behavior?

1. Calculate ∆G° for the combustion of ethane 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(l)   With the following ∆G°f:                        C2H6(g) = -32.86 kJ/mol                        CO2(g) = -394.4 kJ/mol                        H2O(l) = -237.2 kJ/mol

Calculate ΔrG° for the following reaction at 387 K. HCN(g) + 2H2(g) → CH3NH2(g)    ΔrH°= -158.0kJmol-1; ΔrS°= -219.9JK-1 mol-1

Calculate ∆H for the reaction 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g), from the following data. 1. N2 (g) + O2 (g) → 2NO (g) ∆H = -180.5 kJ 2. N2 (g) + 3H2 (g) → 2 NH3 (g) ∆H = -91.8 kJ 3. 2H2 (g) + O2 (g) → 2H2O (g) ∆H = -483.6 kJ

If ∆H < 0 and ∆S < 0, a reaction will be:

O(g) + e–(g) --> O–(g)    ∆Hº = –142 kJ mol–1 O(g) + 2 e–(g) --> O 2– (g) ∆Hº = +702 kJ mol–1 What is ∆Hº for the following reaction? O–(g) + e–(g) --> O 2– (g)

The accompanying diagram shows how ∆H (red line) and T∆S (blue line) change with temperature for a hypothetical reaction. (a) What is the significance of the point at 300 K, where ∆H and T∆S are equal?

3) The enzyme aldolase catalyzes the conversion of fructose-1,6-diphosphate (FDP)to dihydroxyacetone phosphate (DHAP) and glyceraldehide-3-phosphate (G3P). Thereaction isFDP ⇄ DHAP + G3P , ∆rG0(298.15 K) = 23.8 kJ mol−1In red blood cells the concentration of these species are [FDP] = 35 µM, [DHAP] =130 µM, and [G3P] = 15 µM. (Remember that 1.0 µM = 1.0 × 10−6 mol L−1. Thestandard state for reactions in solution can be taken as c0 = 1.0 mol L−1).Calculate ∆rG in a red blood cell at 25 0C. Will the reaction occur spontaneouslyin the cell at this temperature?

The standard free energy variation, at 25 ºC, for equilibrium: Glucose-6-phosphate (G-6-P) Glucose-1-phosphate (G-1-P) is ΔGº '= + 7280 J / mol. Calculate a) The equilibrium constant of the reaction. b) The real change in free energy when one mole of G-6-P is transformed into G-1-P, both concentrations remaining constant and equal to 10mM and 2 mM respectively.