Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
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The expression for ∆H° of formation of CO2 as a function of temperature is ∆Ho = -93480–0.603T–0.675x10-4T2-1.091x105/T. Find the ∆Cpo for this reaction as a function of T.
11. This reaction must have a ∆G>0 at SATP:
2O3(g)→3O2(g)
C(s)+O2(g)→CO2(g)
2K(s)+F2(g)→KF2(s)
2Fe2O3(s)→4Fe(s)+3O2(g)
Calculate ∆rHofor the overall reaction 3P + Q → S, given the following data below: 2P + 3Q → R + T ∆rHo = -64 kJ/mol ---------(1)S + P → R ∆rHo = 100 kJ/mol ----------(2)P + ½T → Q ∆rHo = 74 kJ/mol ---------(3)
Chapter 12 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 12 - Prob. 12.1VPCh. 12 - Prob. 12.2VPCh. 12 - Prob. 12.4VPCh. 12 - Prob. 12.5VPCh. 12 - Prob. 12.6VPCh. 12 - Prob. 12.8VPCh. 12 - Prob. 12.9VPCh. 12 - Prob. 12.10VPCh. 12 - Prob. 12.11QACh. 12 - Prob. 12.12QA
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- For the decomposition of formic acid, HCOOH(l)H2O(l)+CO(g) H = +29 kJ/mol at 25C. a Does the tendency of this reaction to proceed to a state of minimum energy favor the formation of water and carbon monoxide or formic acid? Explain. b Does the tendency of this reaction to proceed to a state of maximum entropy favor the formation of products or reactants? Explainarrow_forwardCisplatin [cis-diamminedichloroplatinum(II)] is a potent treatment for certain types of cancers, but the trans isomer is not effective. What is the equilibrium constant at 298 K for the transformation of the cis to the trans isomer? Which is the favored isomer at 298 K, the cis or the trans isomer?arrow_forwardWhat is the ∆H, ∆S, and ∆G when we isothermally mix 1.0 mol of toluene and 2.5 mol of benzene,assuming ideal behavior?arrow_forward
- 1. Calculate ∆G° for the combustion of ethane 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(l) With the following ∆G°f: C2H6(g) = -32.86 kJ/mol CO2(g) = -394.4 kJ/mol H2O(l) = -237.2 kJ/molarrow_forwardUnder base-catalyzed conditions, two molecules of acetone can condense to form diacetone alcohol. At room temperature (25 °C), about 5% of the acetone is converted to diacetone alcohol. Determine the value of ∆G° for this reaction.arrow_forwardAn example of a reaction where ∆G = 0 is a. any reaction that has reached completion b. 2H2(g)+O2(g)→2H2O(g) c. 2H2(g)+O2(g)→2H2O(l) d. only reversible reactionsarrow_forward
- O(g) + e–(g) --> O–(g) ∆Hº = –142 kJ mol–1 O(g) + 2 e–(g) --> O 2– (g) ∆Hº = +702 kJ mol–1 What is ∆Hº for the following reaction? O–(g) + e–(g) --> O 2– (g)arrow_forwardCalculate ΔrG° for the following reaction at 387 K. HCN(g) + 2H2(g) → CH3NH2(g) ΔrH°= -158.0kJmol-1; ΔrS°= -219.9JK-1 mol-1arrow_forwardIf ∆H < 0 and ∆S < 0, a reaction will be:arrow_forward
- The accompanying diagram shows how ∆H (red line) and T∆S (blue line) change with temperature for a hypothetical reaction. (a) What is the significance of the point at 300 K, where ∆H and T∆S are equal?arrow_forwardWhat is the ∆G° and equilibrium constant at 298 K for the following reaction? 2Cl2(g) + SO2(g) SOCl2(g) + Cl2O(g) Substance ∆H°(kJ/mol) ∆S°(J/K mol) Cl2(g) 0 223.0 SO2(g) -296.8 248.1 SOCl2(g) -212.5 309.8 Cl2O(g) 80.3 266.1arrow_forwardCalculate the ∆S 0 for each given reaction. 1. 2H2 (g) + O2 (g) ---> 2H2O (g) 2. Ca3(PO4)2 (s) ---> 3Ca+2 (aq) + 2PO4 -3 (aq)arrow_forward
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