Bundle: Principles Of Geotechnical Engineering, Loose-leaf Version, 9th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
9th Edition
ISBN: 9781337583848
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 12, Problem 12.20P
To determine
Find the deviator stress at failure.
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x in red is equal to 39
A consolidated-undrained test determines that the shear strength of a normally consolidated clay is given by τf = σ’tan 27o. The confining pressure is 150 kPa, and deviator stress at failure is 120 kPa.• Find the consolidated-undrained friction angle• Pore water pressure developed in the specimen at failureFinal answer should be in 3 decimal places.
5- The shear strength of a normally consolidated clay can be given by the equation tf o'tan 27°. Following are the
results of a
consolidated-undrained
test on the clay.
• Chamber-confining pressure = 3,130 lb/ft²
Deviator stress at failure = 2,510 lb/ft²
a) Determine the consolidated-undrained friction angle
b) Pore-water pressure developed in the specimen at failure
Chapter 12 Solutions
Bundle: Principles Of Geotechnical Engineering, Loose-leaf Version, 9th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Following are the results of...Ch. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.1CTP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- Please answer 12.17arrow_forwardA consolidated undrained triaxial test was performed on a normally consolidated clay with a critical state friction angle of 230. After an initial isotropic consolidation at a cell pressure of 50 kPa, drainage was turned off, the cell pressure was increased to 85 kPa, and the sample was loaded to ultimate conditions. A pore pressure of 55 kPa was measured at ultimate state. What value of major principal total stress was measured at the ultimate state?arrow_forwardA triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure were determined to be 6100 psf and 4600 psf, respectively. a. Determine the angle of internal friction of the sand? b. Determine the angle of the failure plane? c. Determine the maximum principal stress? Please answer this asap. For upvote. Thank you very mucharrow_forward
- Tri-Axial Testsarrow_forwardA consolidated-drained triaxial test was conducted on a normally consolidated clay. The results were as follows: Determine: a. Angle of friction, f? b. Angle u that the failure plane makes with the major principal plane c. Normal stress, s?, and shear stress, tf , on the failure planearrow_forwardData from an oedometer test using a clay specimen are plotted in the graph shown below. If the compression index is equal to 0.6, calculate the void ratio (e2) missing at Point C, which is associated with a vertical effective stress equal to 105 kPaarrow_forward
- A consolidated-drained triaxial test was conducted on a normally consolidated clay. The results were as follows: Determine: a. Angle of friction, f? b. Angle u that the failure plane makes with the major principal plane c. Normal stress, s?, and shear stress, tf , on the failure planearrow_forwardThe shear strength of a normally consolidated clay can be given by theequation (tau)f=(sigma prime)tan(21). The results of a consolidated-undrained test on theclay areChamber confining pressure 5 225 kN/m2Deviator stress at failure 5 112 kN/m2Determine:a. The consolidated-undrained (total stress) friction angleb. Pore water pressure developed in the specimen at failurearrow_forwardA consolidated-drained triaxial test was conducted on a normally consolidated clay. The results kN o', = 276 kN (A0,), = 276 m² are as follows: Determine: (a) The angle of friction o; (b) The angle 0 that the failure plane makes with the major principal plane, and (c) The normal stress o’ and shear stress t, on the failure plane.arrow_forward
- A consolidated-undrained test on a normally consolidate clay yield the following results: Confining Pressure 167 KPa; Deviator Stress = 184 KPa; Pore Pressure = 74 KPa. Calculate the normal stress at the failure plane at drained condition in KPa.arrow_forwardIn an Oedometer apparatus, a specimen of fully saturated clay has been consolidated under a vertical pressure of 50 kN/m2 and is presently at equilibrium. The effective stress and pore water pressure immediately on increasing the vertical stress to 150 kN/m2, respectively are...?arrow_forwardProb.5. Samples of a dry sand are to be tested in triaxial and direct shear test. In the triaxial test the specimen fails when the major and minor principal stress are 960 kN/m² and 260 kN/m² respectively. What shear strength would be expected in direct shear test, when normal stress is 230 kN/m²?arrow_forward
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