Explanation Given Information: The function is f ( x ) = 2 x 2 − 5 x + 10 . Formula used: Consider a general quadratic function f ( x ) = a x 2 + b x + c , It can be written in the form f ( x ) = a ( x − h ) 2 + k . Where h = − 1 2 ⋅ a ⋅ b and k is sum of remaining constant terms. Calculation: Consider the function f ( x ) = 2 x 2 − 5 x + 10 . Compare it with general form of quadratic function f ( x ) = a x 2 + b x + c . Put a = 2 and b = − 5 in the equation h = − 1 2 a ⋅ b , h = − 1 2 ⋅ ( 2 ) ⋅ ( − 5 ) h = 5 4 Add and subtract h 2 = 25 16

Elementary and Intermediate Algebra: Concepts and Applications (7th Edition)

7th Edition

ISBN: 9780134462707

Author: Marvin L. Bittinger, David J. Ellenbogen, Barbara L. Johnson

Publisher: PEARSON

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Chapter 11.7, Problem 17ES

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To calculate: The form f(x)=a(x−h)2+k of the function f(x)=2x2−5x+10.

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Chapter 11.7, Problem 16ES

Chapter 11.7, Problem 18ES

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Chapter 11 Solutions

Elementary and Intermediate Algebra: Concepts and Applications (7th Edition)

Ch. 11.1 - Solve: 64=y2.Ch. 11.1 - Solve: t2=10. Give exact solutions and...Ch. 11.1 - Prob. 3YT Ch. 11.1 - Prob. 4YT Ch. 11.1 - Prob. 5YT Ch. 11.1 - 6. Solve: . Ch. 11.1 - Prob. 7YT Ch. 11.1 - Prob. 8YT Ch. 11.1 - Prob. 9YT Ch. 11.1 - Prob. 10YT

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The form f ( x ) = a ( x − h ) 2 + k of the function f ( x ) = 2 x 2 − 5 x + 10 .

Solution Summary: The author compares the form of the function f(x) to the general quadratic function, where a=2andb=-5 is sum of remaining constant terms.

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To calculate: The form f(x)=a(x−h)2+k of the function f(x)=2x2−5x+10.

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Chapter 11 Solutions