Explanation Definition used: Definition 1: “A planet around the sun one in elliptical orbit with sun at one focus. The perihelion distance of planet to the sun is a ( 1 − e ) . The aphelion distance of the planet to the sun is a ( 1 + e ) ”. Calculation: The perihelion and aphelion distances to the sun is 4.43 × 10 9 km and 7.37 × 10 9 km. That is, by definition stated above, Thus, the perihelion distance a ( 1 − e ) = 4.43 × 10 9 and the aphelion distance a ( 1 + e ) = 7.37 × 10 9 . Use above equation and find the value of e as follows. a ( 1 + e ) a ( 1 − e ) = 7.37 × 10 9 4

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ISBN: 9781337037785

Author: Stewart

Publisher: CENGAGE C

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Chapter 11.6, Problem 45E

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To find: The eccentricity of Pluto’s orbit with the distance from the sun is 4.43×109 km at perihelion and 7.37×109 km at aphelion.

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Chapter 11.6, Problem 44E

Chapter 11.6, Problem 46E

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The eccentricity of Pluto’s orbit with the distance from the sun is 4.43 × 10 9 km at perihelion and 7.37 × 10 9 km at aphelion.

Solution Summary: The author explains the eccentricity of Pluto's orbit with the distance from the sun is 0.249.

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To find: The eccentricity of Pluto’s orbit with the distance from the sun is 4.43×109 km at perihelion and 7.37×109 km at aphelion.

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Chapter 11 Solutions