Chapter 11.6, Problem 42PPE

To determine

Write an equation to find the length of the second lot.

Answer to Problem 42PPE

  $x_1\cdot y_1=x_2\cdot y_2$ , 121ft

Explanation of Solution

Given information:

Both of the two rectangular building lots shown at the bottom have the same area.

  

Calculation:

The given figure has same area and both are rectangle.

The area of rectangle is = length $\cdot$ breadth

Length of first lot $\left(x_1\right)=110ft$

Breadth of first lot $\left(y_1\right)=99ft$

Breadth of second lot $\left(y_2\right)=90ft$

Equation to find out the length of second lot is

Let length of second lot $=x_2$

  $\begin{array}{c}{x}_1\cdot y_1=x_2\cdot y_2\\ 110\cdot 99=x_2\cdot 90\\ 10890=90x_2\\ x_2=\frac{10890}{90}\\ x_2=121ft\end{array}$

Length of the second lot $x_2=121ft$