Chapter 11.6, Problem 35HP

To determine

To find:Example of a triangle and a parallelogram that have the same area.

Answer to Problem 35HP

Area of the parallelogram = Area of the triangle = $50m^2$

Explanation of Solution

Formula used: Area of parallelogram = base $\times$ height

Calculation:

Consider the following figures:

  

In ∆ABC,

Base = BC = 10 m

Height = AB = 10 m

Area of $\Delta ABC=\frac{1}{2}$ $\times$ (base) $\times$ (height) $=\frac{1}{2}\times (10)\times (10)=50m^2$

In parallelogram PQRS,

Base = SR = 10 m

Height = PT = 5 m

Area of the parallelogram = Base $\times$ height $=5\times 10=50m^2$

So, area of triangle is equal to area of parallelogram.