Glencoe Chemistry: Matter and Change, Student Edition
Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
Question
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Chapter 11.3, Problem 24PP

(a)

Interpretation Introduction

Interpretation:

The balanced chemical equation for given reaction is to be stated.

Concept introduction:

A balanced chemical equation consists of equal number of atoms of all the elements that are present in a chemical reaction.

(a)

Expert Solution
Check Mark

Answer to Problem 24PP

The balanced chemical equation for given reaction is shown below:

6CO2(g)+6H2O(l)C6H12O6(aq)+6O2(g)

Explanation of Solution

The reactants are carbon dioxide and water and the reaction leads to the formation of glucose and oxygen. The chemical equation corresponding to given reaction is shown below:

6CO2(g)+6H2O(l)C6H12O6(aq)+6O2(g)

(b)

Interpretation Introduction

Interpretation:

The limiting reagent in given reaction is to be determined.

Concept introduction:

The formula to calculate the number of moles is given as shown below:

Number of moles=Given massMolar mass

(b)

Expert Solution
Check Mark

Answer to Problem 24PP

Carbon dioxide acts as the limiting reagent.

Explanation of Solution

The molar mass of carbon dioxide is 44.0g/mol. Substitute the given mass and molar mass in the above equation for number of moles.

Number of moles=88.0g44.0gmol=2mol

The molar mass of water is 18.0g/mol. Substitute the given mass and molar mass in the above equation for number of moles.

Number of moles=64.0g18.0gmol=3.56mol

The limiting reagent is determined as shown below:

6molCO2=6molH2O2.0molCO2=66×2molH2O=2molH2O

Thus, the given amount of water is more than required. Therefore, carbon dioxide acts as the limiting reagent.

(c)

Interpretation Introduction

Interpretation:

The excess reagent in given reaction is to be determined.

Concept introduction:

The reagent that gets completely used in reaction is the limiting reagent. The reagent that is left even after the reaction is defined as the excess reagent.

(c)

Expert Solution
Check Mark

Answer to Problem 24PP

Water acts as the excess reagent.

Explanation of Solution

The given moles of water are 3.56mol and the required number of moles is two. Thus, 1.56mol of water are excess. Therefore, water acts as the excess reagent.

(d)

Interpretation Introduction

Interpretation:

The mass of excess reagent is to be stated.

Concept introduction:

The reagent that gets completely used in reaction is the limiting reagent. The reagent that is left even after the reaction is defined as the excess reagent.

(d)

Expert Solution
Check Mark

Answer to Problem 24PP

The mass of excess reagent is 28.08g.

Explanation of Solution

The given moles of water are 3.56mol and the required number of moles is two. Thus, 1.56mol of water are excess. Therefore, water acts as the excess reagent. The molar mass of water is 18.0g/mol. Substitute the number of moles and molar mass in the above equation for number of moles.

1.56=Given mass18.0gmolGiven mass=28.08g

(e)

Interpretation Introduction

Interpretation:

The mass of glucose formed is to be stated.

Concept introduction:

The reagent that gets completely used in reaction is the limiting reagent. The reagent that is left even after the reaction is defined as the excess reagent.

(e)

Expert Solution
Check Mark

Answer to Problem 24PP

The mass of glucose formed is 59.45g.

Explanation of Solution

The moles of glucose formed are calculated as shown below:

6molCO2=1molglucose2.0molCO2=16×2molglucose=0.33molglucose

The molar mass of glucose is 180.156g/mol. Substitute the number of moles and molar mass in the above equation for number of moles.

0.33mol=Given mass180.156gmolGiven mass=59.45g

Chapter 11 Solutions

Glencoe Chemistry: Matter and Change, Student Edition

Ch. 11.2 - Prob. 11PPCh. 11.2 - Prob. 12PPCh. 11.2 - Prob. 13PPCh. 11.2 - Prob. 14PPCh. 11.2 - Prob. 15PPCh. 11.2 - Prob. 16PPCh. 11.2 - Prob. 17SSCCh. 11.2 - Prob. 18SSCCh. 11.2 - Prob. 19SSCCh. 11.2 - Prob. 20SSCCh. 11.2 - Prob. 21SSCCh. 11.2 - Prob. 22SSCCh. 11.3 - Prob. 23PPCh. 11.3 - Prob. 24PPCh. 11.3 - Prob. 25SSCCh. 11.3 - Prob. 26SSCCh. 11.3 - Prob. 27SSCCh. 11.4 - Prob. 28PPCh. 11.4 - Prob. 29PPCh. 11.4 - Prob. 30PPCh. 11.4 - Prob. 31SSCCh. 11.4 - Prob. 32SSCCh. 11.4 - Prob. 33SSCCh. 11.4 - Prob. 34SSCCh. 11.4 - Prob. 35SSCCh. 11 - Prob. 36ACh. 11 - Prob. 37ACh. 11 - Prob. 38ACh. 11 - Prob. 39ACh. 11 - Prob. 40ACh. 11 - Prob. 41ACh. 11 - Prob. 42ACh. 11 - Prob. 43ACh. 11 - Interpret the following equation in terms of...Ch. 11 - Smelting When tin(IV) oxide is heated with carbon...Ch. 11 - When solid copper is added to nitric acid, copper...Ch. 11 - When hydrochloric acid solution reacts with lead...Ch. 11 - When aluminum is mixed with iron(lll) oxide, iron...Ch. 11 - Solid silicon dioxide, often called silica, reacts...Ch. 11 - Prob. 50ACh. 11 - Prob. 51ACh. 11 - Prob. 52ACh. 11 - Antacids Magnesium hydroxide is an ingredient in...Ch. 11 - Prob. 54ACh. 11 - Prob. 55ACh. 11 - Prob. 56ACh. 11 - Prob. 57ACh. 11 - Prob. 58ACh. 11 - Prob. 59ACh. 11 - Ethanol (C2H5OH) , also known as grain alcohol,...Ch. 11 - Welding If 5.50 mol of calcium carbide (CaC2)...Ch. 11 - Prob. 62ACh. 11 - Prob. 63ACh. 11 - Prob. 64ACh. 11 - Prob. 65ACh. 11 - Prob. 66ACh. 11 - Prob. 67ACh. 11 - Prob. 68ACh. 11 - Prob. 69ACh. 11 - Prob. 70ACh. 11 - Prob. 71ACh. 11 - Prob. 72ACh. 11 - Prob. 73ACh. 11 - Prob. 74ACh. 11 - Prob. 75ACh. 11 - Prob. 76ACh. 11 - Prob. 77ACh. 11 - Prob. 78ACh. 11 - Prob. 79ACh. 11 - Prob. 80ACh. 11 - Prob. 81ACh. 11 - Prob. 82ACh. 11 - Prob. 83ACh. 11 - Prob. 84ACh. 11 - Prob. 85ACh. 11 - Prob. 86ACh. 11 - Prob. 87ACh. 11 - Prob. 88ACh. 11 - Prob. 89ACh. 11 - Prob. 90ACh. 11 - Lead(ll) oxide is obtained by roasting galena,...Ch. 11 - Prob. 92ACh. 11 - Prob. 93ACh. 11 - Prob. 94ACh. 11 - Prob. 95ACh. 11 - Prob. 96ACh. 11 - Prob. 97ACh. 11 - Ammonium sulfide reacts With copper(ll) nitrate in...Ch. 11 - Fertilizer The compound calcium cyanamide (CaNCN)...Ch. 11 - When copper(ll) oxide is heated in the presence Of...Ch. 11 - Air Pollution Nitrogen monoxide, which is present...Ch. 11 - Electrolysis Determine the theoretical and percent...Ch. 11 - Iron reacts with oxygen as Shown....Ch. 11 - Analyze and Conclude In an experiment, you obtain...Ch. 11 - Observe and Infer Determine whether each reaction...Ch. 11 - Design an Experiment Design an experiment that can...Ch. 11 - Apply When a campfire begins to die down and...Ch. 11 - Apply Students conducted a lab to investigate...Ch. 11 - When 9.59 g of a certain vanadium oxide is heated...Ch. 11 - Prob. 110ACh. 11 - Prob. 111ACh. 11 - Prob. 112ACh. 11 - Prob. 113ACh. 11 - Prob. 114ACh. 11 - Prob. 115ACh. 11 - Prob. 116ACh. 11 - Prob. 117ACh. 11 - Prob. 118ACh. 11 - Prob. 119ACh. 11 - Prob. 120ACh. 11 - Prob. 1STPCh. 11 - Prob. 2STPCh. 11 - Prob. 3STPCh. 11 - Prob. 4STPCh. 11 - Prob. 5STPCh. 11 - Prob. 6STPCh. 11 - Prob. 7STPCh. 11 - Prob. 8STPCh. 11 - Prob. 9STPCh. 11 - Prob. 10STPCh. 11 - Prob. 11STPCh. 11 - Prob. 12STPCh. 11 - Prob. 13STPCh. 11 - Prob. 14STPCh. 11 - Prob. 15STPCh. 11 - Prob. 16STPCh. 11 - Prob. 17STP
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