Chapter 11.2, Problem 10P

Multiply.

$\left(10x^2-7x+2\right)\cdot \frac{6x^2-13x-63}{3x+7}$

To determine

To multiply : the expression

Answer to Problem 10P

The value of $\frac{6x^2-13x-63}{3x+7}\cdot \left(10x^2-7x+2\right)$ is $20x^3-104x^2+67x-18$

Explanation of Solution

Given information : The expression is $\frac{6x^2-13x-63}{3x+7}\cdot \left(10x^2-7x+2\right)$

Calculation :

  $\begin{array}{l}\frac{6x^2-13x-63}{3x+7}\cdot \left(10x^2-7x+2\right)\\ \Rightarrow \frac{\left(6x^2-13x-63\right)\left(10x^2-7x+2\right)}{3x+7}\\ \Rightarrow \frac{\left(10x^2-7x+2\right)\left(6x^2+14x-27x-63\right)}{3x+7}\\ \Rightarrow \frac{\left(10x^2-7x+2\right)\left(3x+7\right)\left(2x-9\right)}{3x+7}\\ \Rightarrow 20x^3-104x^2+67x-18\end{array}$