
Concept explainers
Approximate the area of the region using the rectangles of equal width shown.

Answer to Problem 96RE
The area under the region is 3.53 square units.
Explanation of Solution
Given:
The given function:
f(x)=4−x2
Here length of the interval along x -axis is 3 units and there are six rectangles, the width of the rectangle is 14
Height of each rectangle can be obtained by evaluating $f$ at the right end point of each interval
The six intervals are as follows:
(0,14)⋅(14,12),(12,34)and(34,1)
The right end point of each interval is 14i for i=1,2,3,4.
Therefore the sum of areas of four rectangles is
∑4i=1f(14i)(14)=∑4i=1(4−(14i)2)(14)=∑4i=1(1−164i2)=∑4i=11−164∑4ii2
Use properties of summation ∑∞i=1i=n(n+1)(2n+1)6 and ∑ni=1c=nc
∑4i=1f(14i)(14)=4−164(4×5×96)=4−180384=3.53
Therefore, the area under the region is 3.53 square units.
Chapter 11 Solutions
Precalculus with Limits: A Graphing Approach
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