Explanation Consider the given relation. x 2 + y 2 = 25 (1) Simplify further for the value of y . y 2 = 25 − x 2 y = ± 25 − x 2 Thus, y = ϕ 1 ( x ) = 25 − x 2 And, y = ϕ 2 ( x ) = − 25 − x

Advanced Engineering Mathematics

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ISBN: 9781284105902

Author: Dennis G. Zill

Publisher: Jones & Bartlett Learning

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Chapter 1.1, Problem 53E

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The reason for which the interval over which explicit solutions are defined can’t be the closed interval.

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Chapter 1.1, Problem 52E

Chapter 1.1, Problem 54E

Chapter 1 Solutions

Advanced Engineering Mathematics

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

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Finding Local Maxima and Minima by Differentiation; Author: Professor Dave Explains;https://www.youtube.com/watch?v=pvLj1s7SOtk;License: Standard YouTube License, CC-BY

The reason for which the interval over which explicit solutions are defined can’t be the closed interval.

Solution Summary: The author explains that the closed interval of left[-5,5right] cannot be considered as the largest interval where the solution is defined.

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The reason for which the interval over which explicit solutions are defined can’t be the closed interval.

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Chapter 1 Solutions