Chapter 11, Problem 50QAP

To determine

(a)

Convert $1500\text{kPa}$ to ${\text{N/m}}^{\text{2}}$

Answer to Problem 50QAP

  $1500\text{kPa}$ is equal to $15\times {10}^5{\text{N/m}}^{\text{2}}$

Explanation of Solution

Given info:

Pressure, $P=1500\text{kPa}$

Calculation:

The value of $1500\text{kPa}$ in ${\text{N/m}}^{\text{2}}$ is calculated as

  $\begin{array}{c}1500\text{kPa}=1500\times {10}^3\text{Pa}\left(\because 1\text{kPa}=1\times {10}^3\text{Pa}\right)\\ \text{=15}\times {\text{10}}^5{\text{N/m}}^{\text{2}}\end{array}$

Conclusion:

  $1500\text{kPa}$ is equal to $15\times {10}^5{\text{N/m}}^{\text{2}}$

To determine

(b)

Convert $35\text{psi}$ to ${\text{N/m}}^{\text{2}}$

Answer to Problem 50QAP

  $35\text{psi}$ is equal to $241317{\text{N/m}}^{\text{2}}$

Explanation of Solution

Given info:

Pressure, $35\text{psi}$

Calculation:

The value of $35\text{psi}$ in ${\text{N/m}}^{\text{2}}$ is calculated as

  $\begin{array}{c}35\text{psi}=35\times 6894.76{\text{N/m}}^{\text{2}}\left(\because 1\text{psi}=\text{6894}\text{.76}{\text{N/m}}^2\right)\\ =241317{\text{N/m}}^{\text{2}}\end{array}$

Conclusion:

  $35\text{psi}$ is equal to $241317{\text{N/m}}^{\text{2}}$

To determine

(c)

Convert $2.85\text{atm}$ to ${\text{N/m}}^{\text{2}}$

Answer to Problem 50QAP

  $2.85\text{atm}$ is equal to $\text{2}\text{.87}\times {\text{10}}^5{\text{N/m}}^{\text{2}}$

Explanation of Solution

Given info:

Pressure, $2.85\text{atm}$

Calculation:

The value of $2.85\text{atm}$ in ${\text{N/m}}^{\text{2}}$ is calculated as

  $\begin{array}{c}2.85\text{atm}=2.85\times 1.01\times {10}^5\text{Pa}\left(\because 1\text{atm}=1.01\times {10}^5\text{Pa}\right)\\ =\text{2}\text{.87}\times {\text{10}}^5{\text{N/m}}^{\text{2}}\end{array}$

Conclusion:

  $2.85\text{atm}$ is equal to $\text{2}\text{.87}\times {\text{10}}^5{\text{N/m}}^{\text{2}}$

To determine

(d)

Convert $883\text{torr}$ to ${\text{N/m}}^{\text{2}}$

Answer to Problem 50QAP

  $883\text{torr}$ is equal to $117721.52{\text{N/m}}^{\text{2}}$.

Explanation of Solution

Given info:

Pressure, $883\text{torr}$

Calculation:

The value of $883\text{torr}$ in ${\text{N/m}}^{\text{2}}$ is calculated as

  $\begin{array}{c}883\text{torr}=883\times 133.32\text{Pa}\left(\because 1\text{torr}=133.32\text{Pa}\right)\\ =117721.52{\text{N/m}}^{\text{2}}\end{array}$

Conclusion:

  $883\text{torr}$ is equal to $117721.52{\text{N/m}}^{\text{2}}$.