Chapter 11, Problem 4STP

To determine

To evaluate: the point that lies on the graph of $\left(gof\right)\left(x\right)$ where $f\left(x\right)=2x^2$ and $g\left(x\right)=\sqrt{x+1}$ .

Answer to Problem 4STP

The correct option is (C).

Explanation of Solution

Given:

The equation represents the height of a thrown object, where h is the height (in feet) and t is the time (in seconds).

  $h=-16t^2+32t+49$

If the object hits the ground means its height is zero,

So,

  $\begin{array}{l}h=-16t^2+32t+49\\ -16t^2+32t+49=0\end{array}$

Finding the value of ‘ t’ by plotting in the graph,

  

So, the value of t should be 3 seconds.

Hence, the correct option is (C).