Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 11, Problem 34P
To determine
The mass of Earth from the period of the moon and its orbital radius.
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The ratio of the radius of the earth to that
of the moon is 10. The ratio of acceleration due
to gravity on the earth to the moon is 6. The
ratio of escape velocity from earth's surface to
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(a) 10
(b) 6
(c) 1.66
(d) 7.74
) One of the moors of Jupiter, named an orbital radius of 10 4.22 * 10 ^ 8 a period of 1.77 days. Assuming the orbitis circular, calculate the inass of Jupiter. (b) largest moon of Jupiter, named Ganymede, has an orbital radius of 1.07 * 10 ^ 9 m a period of 7.16 daysCalculate the mass of Jupiter from this data ) your results to parts (b) consistent ? Yes No Explain
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Chapter 11 Solutions
Physics for Scientists and Engineers
Ch. 11 - Prob. 1PCh. 11 - Prob. 2PCh. 11 - Prob. 3PCh. 11 - Prob. 4PCh. 11 - Prob. 5PCh. 11 - Prob. 6PCh. 11 - Prob. 7PCh. 11 - Prob. 8PCh. 11 - Prob. 9PCh. 11 - Prob. 10P
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- What is the orbital radius of an Earth satellite having a period of 1.00 h? (b) What is unreasonable about this result?arrow_forwardCalculate the effective gravitational field vector g at Earths surface at the poles and the equator. Take account of the difference in the equatorial (6378 km) and polar (6357 km) radius as well as the centrifugal force. How well does the result agree with the difference calculated with the result g = 9.780356[1 + 0.0052885 sin 2 0.0000059 sin2(2)]m/s2 where is the latitude?arrow_forwardShow that for eccentricity equal to one in Equation 13.10 for conic sections, the path is a parabola. Do this by substituting Cartersian coordinates, x and y, for the polar coordinates, r and , and showing that it has the general form for a parabola, x=ay2+by+c .arrow_forward
- Let gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)arrow_forwardOn a planet whose radius is 1.2107m , the acceleration due to gravity is 18m/s2 . What is the mass of the planet?arrow_forwardIf a planet with 1.5 times the mass of Earth was traveling in Earth’s orbit, what would its period be?arrow_forward
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