To Compute : The area and perimeter of the given figure.
Answer to Problem 2PT
The perimeter and area of the given figure are 92.5 in and 500 in2respectively.
Explanation of Solution
Given information :
Using Pythagoras theorem,
And,
Therefore,
Perimeter of (ABFC) = Sum of lengths of all the sides of (ABFC)
= Length of (AB + BF + FC + AC)
=
Area of (ABFC) = Area of (
As,
Implies,
Area of (
Area of (
And as,
Implies,
Area of rectangle (ABED) =
Therefore,
Area of (ABFC) = 20 + 100 + 380 = 500 in2.
Thus,
The perimeter and area of the given figure are 92.5 in and 500 in2respectively.
Chapter 11 Solutions
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