PEARSON ETEXT ENGINEERING MECH & STATS
PEARSON ETEXT ENGINEERING MECH & STATS
15th Edition
ISBN: 9780137514724
Author: HIBBELER
Publisher: PEARSON
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Chapter 11, Problem 27P
To determine

The positions for equilibrium and investigate the stability for each position.

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Three forces, FA, FB, and FC, intersect at the origin. Only 2 of these forces are shown on the diagram. Find the magnitude of FC and its direction coordinate angles for equilibrium, given:FA = 825 N, α = 150 °, β = 75 °FB = 600 N, θ = 20 °, Φ = 30 °
Three forces, FA, FB, and FC, intersect at the origin. Only 2 of these forces are shown on the diagram. Find the magnitude of FC and its direction coordinate angles for equilibrium, given:FA = 825 N, α = 150 °, β = 75 °FB = 600 N, θ = 20 °, Φ = 30 °   Answers  The magnitude of FC is:     FC = 798 N     FC = 455 N     FC = 331 N     FC = 308 N     FC = 522 N   The direction coordinates angles of FC are: αC      αC=69.1 °      αC=60.2 °      αC=40.7 °      αC=106 °      αC=43.8 °   βC       βC=101 °     βC=262 °     βC=149 °     βC=171 °     βC=109 °   γC     γC=65.3 °     γC=70.3 °     γC=111 °     γC=96.7 °     γC=1.70E2 °
If the potential energy for a conservative one degree-of-freedom system is expressed by the relation V = (24 sinθ + 10 cos 2θ ) ft⋅lb, 0° ≤ θ  ≤ 180°,  a) Determine the equilibrium positions,  b) Investigate the stability at each position.
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