Elements of Electromagnetics
Elements of Electromagnetics
7th Edition
ISBN: 9780190698669
Author: Sadiku
Publisher: Oxford University Press
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Chapter 11, Problem 13P

(a)

To determine

Calculate the values of Z and γ.

(a)

Expert Solution
Check Mark

Answer to Problem 13P

The values are Z=644.3j97Ω and γ=(5.415+j33.97)×1031mi.

Explanation of Solution

Calculation:

Consider the general expression for characteristic impedance of the line.

Zo=R+jωLG+jωC        (1)

Here,

R, L, G, and C are line parameters.

Consider the general expression for angular frequency.

ω=2πf

Here,

f is the frequency.

Substitute 1 kHz for f in above equation.

ω=2π(1×103Hz)=6283.18Hz

Simplify the value of L.

L=3.4(103Hmi)=3.4×103Hmi

Simplify the value of C.

C=8.4(109Fmi)=8.4×109Fmi

Simplify the value of G.

G=0.42(106Smi)=4.2×107Smi

Substitute 6283.18 for ω, 3.4×103 for L, 8.4×109 for C, 6.8 for R, and 4.2×107 for G in Equation (1).

Zo=(6.8)+j(6283.18)(3.4×103)(4.2×107)+j(6283.18)(8.4×109)=6.8+j21.364.2×107+j5.278×105=424698.1817.20°=651.688.6°Ω

Convert polar form into rectangular form in above equation.

Zo=644.3j97ΩZ=644.3j97Ω

Consider the general expression for propagation constant.

γ=(R+jωL)(G+jωC)        (2)

Substitute 6283.18 for ω, 3.4×103 for L, 8.4×109 for C, 6.8 for R, and 4.2×107 for G in Equation (2).

γ=[(6.8)+j(6283.18)(3.4×103)][(4.2×107)+j(6283.18)(8.4×109)]=(6.8+j21.36)(4.2×107+j5.278×105)=1.1831×103161.885°=0.034480.9425°

Convert polar form into rectangular form in above equation.

γ=(5.415+j33.97)×1031mi        (3)

Conclusion:

Thus, the values are Z=644.3j97Ω and γ=(5.415+j33.97)×1031mi.

(b)

To determine

Calculate the phase velocity.

(b)

Expert Solution
Check Mark

Answer to Problem 13P

The phase velocity is 1.85×105mis.

Explanation of Solution

Calculation:

Consider the general expression for propagation constant.

γ=α+jβ        (4)

Refer to Part (a).

On comparing imaginary part of Equation (3) and (4),

β=33.97×103

Consider the general expression for wave velocity.

u=ωβ        (5)

Here,

β is linear function of frequency.

Substitute 6283.18 for ω and 33.97×103 for β in Equation (5).

u=6283.1833.97×103=184962mis=1.84962×105mis1.85×105mis

Conclusion:

Thus, the phase velocity is 1.85×105mis.

(c)

To determine

Calculate the wavelength.

(c)

Expert Solution
Check Mark

Answer to Problem 13P

The wavelength is 185.02mi.

Explanation of Solution

Calculation:

Consider the general expression for wavelength.

λ=2πβ        (6)

Substitute 33.97×103 for β in Equation (6).

λ=2π33.97×103=185.02mi

Conclusion:

Thus, the wavelength is 185.02mi.

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Chapter 11 Solutions

Elements of Electromagnetics

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