Concept explainers
Interpretation:
The products that are result of
Concept introduction:
A conjugated diene undergoes an electrophilic addition with Bronsted acids and yields a mixture of isomeric products. Both products are produced from the same carbocation intermediate. The intermediate has two resonance structures, one with a positive charge on C2 and one with a positive charge on C4. In the resonance hybrid, therefore, each of those two C atoms bears a partial positive charge, so each can be attacked by anions. The
Want to see the full answer?
Check out a sample textbook solutionChapter 11 Solutions
Organic Chemistry: Principles And Mechanisms
- Draw the expected product of the given reaction. H HBr Strategy: Identify the type of reaction that will occur. Determine the regiochemistry of the addition reaction. Analyze the carbocation formed and determine whether a rearrangement will occur. If so, rearrange to form a more stable carbocation and complete the nucleophilic addition. Step 6: The last step of the hydrohalogenation reaction is the addition of the bromide ion to the carbocation. Draw the product with non-bonding electrons, where applicable. Select Draw Rings More Erase H Br :Br: сarrow_forwardDraw the products in attached reaction?arrow_forwardQUESTION 9 Fill in the blanks with either "syn" or "anti". The stereochemistry found in the product of an electrophilic addition to an alkene is related to the mechanism of the reaction. Usually | additions result from both new groups adding in a single concerted step. Whereas additions result from a 2-step addtion.arrow_forward
- Finish the indicated reaction by filling in and starting materials, reagents or products as needed arrow_forwardDraw the substitution product formed in the reaction. CH3 CH3 **** H3C- H₂ Br H₂O Draw the product. Incorrect CH3 CH3 K H₂Cc - | OH UI BrHarrow_forwardpls help with both questionsarrow_forward
- Draw the products of each nucleophilic substitution reaction.arrow_forwardDraw the kinetic and thermodynamic addition products formed when one equivalent of HBr reacts with the diene shown. HBr a Products (1 equiv.) Strategy: Step 1: Draw the carbocations formed from addition of proton to each alkene. Step 2: Classify the carbocations and determine the major intermediate. Step 3: Draw the resonance structure for the major intermediate. Step 4: Draw the 1,2 and 1,4 addition products. Step 5: Identify the kinetic and thermodynamic products. Step 1: Addition of HBr to a diene will be similar to the addition of HBr to an alkene. The first step will be protonation of the alkene to form a carbocation, followed by nucleophilic addition of the halide to form a new C-Br bond. The difference is that there are two different alkenes, so four possible carbocations can be formed. Draw the two possible carbocations formed from addition Draw the two possible carbocations formed from addition of a proton to alkene a. of a proton to alkene b.arrow_forwardDraw an energy diagram of the following reactions. A one step reaction with a positive AG A one step reaction with a negative AG A two-step reaction with an overall positivel-Where the intermediates are lower energy than the reactants and the first transition state is lower in energy than the second.arrow_forward
- SHOW THE MECHANISM AND LABEL THE MAJOR PRODUCT/S OF THE GIVEN REACTION.arrow_forwardCurved arrows are used to illustrate the flow of electrons. Follow the arrows and draw the intermediate and product in this reaction. Include all lone pairs. Ignore stereochemistry. Ignore inorganic byproducts. H₂C > :0: Qarrow_forwardPlease helparrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning