(a) Interpretation: The total β % and the % eutectic microconstituent for 10 % S n at room temperature needs to be determined. Concept Introduction: The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'. It appears in solid form. It appears in various shapes like wire, ingot, foil, bar, ribbon etc. It appears in silver color. Its melting point is 182-215 degree Celsius. Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Question

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Answer 1

Question

Chapter 11, Problem 11.26P

Interpretation Introduction

(a)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $10%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, ingot, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $10%Sn$ is 8.2% and 0% respectively.

Explanation of Solution

Given:

$10%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 1

Calculations:

From the graph,

For % $β$ = $10−299−2$ =8.2%

% Eutectic = 0.

Thus, the evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 10% Sn is calculated as 8.2% and 0% respectively.

Interpretation Introduction

(b)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $20%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $20%Sn$ is 18.6% and 2.3% respectively.

Explanation of Solution

Given:

$20%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 2

Calculations:

From the graph,

For % $β$ = $20−299−2=$ 18.6%

% Eutectic = $50−1961.9−19$ =2.3%

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 20% Sn is calculated as 18.6% and 2.3% respectively.

Interpretation Introduction

(c)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $50%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $50%Sn$ is 49.5% and 72.3% respectively.

Explanation of Solution

Given:

$50%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 3

Calculations:

From the diagram,

For % $β$ = $50−299−2=49.5%$

% Eutectic = $60−1961.9−19=72.3%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 50% Sn is calculated as 49.5% and 72.3% respectively.

Interpretation Introduction

(d)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $60%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire,foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $60%Sn$ is 59.8% and 95.6% respectively.

Explanation of Solution

Given:

$60%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 4

Calculations:

From the graph,

For % $β$ = $60−299−2=59.8%$

% Eutectic = $97.5−1961.9−19=95.6%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 60% Sn is calculated as 59.8% and 95.6% respectively.

Interpretation Introduction

(e)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $80%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $80%Sn$ is 80.4% and 49.2% respectively.

Explanation of Solution

Use spreadsheet to tabulate the % total $β$ and % eutectic micro constituent as in table (1)

Composition of % $Sn$ in entire $Pb−sn$ phase diagram	Tensile Strength ( $MPa$ )	Total % $β$ phase	% Eutectic
10	30	8.2	0
20	40	18.6	2.3
50	50	49.5	72.3
60	60	59.8	95.6
80	70	80.4	49.6
95	80	95.9	7

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 5

Given:

$80%Sn$

Calculations:

From the graph:

For % $β$ = $80−299−2=80.4%$

% Eutectic = $97.5−8097.5−61.9=49.2%$

Thus, by using the expression of eutectic, the required value obtained is 49.2%.

Interpretation Introduction

(f)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $95%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $95%Sn$ is 95.9% and 7.0% respectively.

Explanation of Solution

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 6

Given:

$95%Sn$

Calculations:

For % $β$ = $95−299−2=95.9%$

% Eutectic = $97.5−9597.5−61.9=7.0%$

(Mention Graph)

After Studying the graph of tensile strength vs % $β$ we can conclude that as tensile strength increases to its maximum value of 7800psi at % $β$ = 60%.

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 95% Sn is calculated as 95.9% and 7.0% respectively.

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Answer 2

Question

Chapter 11, Problem 11.26P

Interpretation Introduction

(a)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $10%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, ingot, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $10%Sn$ is 8.2% and 0% respectively.

Explanation of Solution

Given:

$10%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 1

Calculations:

From the graph,

For % $β$ = $10−299−2$ =8.2%

% Eutectic = 0.

Thus, the evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 10% Sn is calculated as 8.2% and 0% respectively.

Interpretation Introduction

(b)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $20%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $20%Sn$ is 18.6% and 2.3% respectively.

Explanation of Solution

Given:

$20%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 2

Calculations:

From the graph,

For % $β$ = $20−299−2=$ 18.6%

% Eutectic = $50−1961.9−19$ =2.3%

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 20% Sn is calculated as 18.6% and 2.3% respectively.

Interpretation Introduction

(c)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $50%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $50%Sn$ is 49.5% and 72.3% respectively.

Explanation of Solution

Given:

$50%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 3

Calculations:

From the diagram,

For % $β$ = $50−299−2=49.5%$

% Eutectic = $60−1961.9−19=72.3%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 50% Sn is calculated as 49.5% and 72.3% respectively.

Interpretation Introduction

(d)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $60%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire,foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $60%Sn$ is 59.8% and 95.6% respectively.

Explanation of Solution

Given:

$60%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 4

Calculations:

From the graph,

For % $β$ = $60−299−2=59.8%$

% Eutectic = $97.5−1961.9−19=95.6%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 60% Sn is calculated as 59.8% and 95.6% respectively.

Interpretation Introduction

(e)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $80%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $80%Sn$ is 80.4% and 49.2% respectively.

Explanation of Solution

Use spreadsheet to tabulate the % total $β$ and % eutectic micro constituent as in table (1)

Composition of % $Sn$ in entire $Pb−sn$ phase diagram	Tensile Strength ( $MPa$ )	Total % $β$ phase	% Eutectic
10	30	8.2	0
20	40	18.6	2.3
50	50	49.5	72.3
60	60	59.8	95.6
80	70	80.4	49.6
95	80	95.9	7

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 5

Given:

$80%Sn$

Calculations:

From the graph:

For % $β$ = $80−299−2=80.4%$

% Eutectic = $97.5−8097.5−61.9=49.2%$

Thus, by using the expression of eutectic, the required value obtained is 49.2%.

Interpretation Introduction

(f)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $95%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $95%Sn$ is 95.9% and 7.0% respectively.

Explanation of Solution

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 6

Given:

$95%Sn$

Calculations:

For % $β$ = $95−299−2=95.9%$

% Eutectic = $97.5−9597.5−61.9=7.0%$

(Mention Graph)

After Studying the graph of tensile strength vs % $β$ we can conclude that as tensile strength increases to its maximum value of 7800psi at % $β$ = 60%.

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 95% Sn is calculated as 95.9% and 7.0% respectively.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 11, Problem 11.26P

Interpretation Introduction

(a)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $10%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, ingot, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $10%Sn$ is 8.2% and 0% respectively.

Explanation of Solution

Given:

$10%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 1

Calculations:

From the graph,

For % $β$ = $10−299−2$ =8.2%

% Eutectic = 0.

Thus, the evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 10% Sn is calculated as 8.2% and 0% respectively.

Interpretation Introduction

(b)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $20%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $20%Sn$ is 18.6% and 2.3% respectively.

Explanation of Solution

Given:

$20%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 2

Calculations:

From the graph,

For % $β$ = $20−299−2=$ 18.6%

% Eutectic = $50−1961.9−19$ =2.3%

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 20% Sn is calculated as 18.6% and 2.3% respectively.

Interpretation Introduction

(c)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $50%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $50%Sn$ is 49.5% and 72.3% respectively.

Explanation of Solution

Given:

$50%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 3

Calculations:

From the diagram,

For % $β$ = $50−299−2=49.5%$

% Eutectic = $60−1961.9−19=72.3%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 50% Sn is calculated as 49.5% and 72.3% respectively.

Interpretation Introduction

(d)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $60%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire,foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $60%Sn$ is 59.8% and 95.6% respectively.

Explanation of Solution

Given:

$60%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 4

Calculations:

From the graph,

For % $β$ = $60−299−2=59.8%$

% Eutectic = $97.5−1961.9−19=95.6%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 60% Sn is calculated as 59.8% and 95.6% respectively.

Interpretation Introduction

(e)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $80%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $80%Sn$ is 80.4% and 49.2% respectively.

Explanation of Solution

Use spreadsheet to tabulate the % total $β$ and % eutectic micro constituent as in table (1)

Composition of % $Sn$ in entire $Pb−sn$ phase diagram	Tensile Strength ( $MPa$ )	Total % $β$ phase	% Eutectic
10	30	8.2	0
20	40	18.6	2.3
50	50	49.5	72.3
60	60	59.8	95.6
80	70	80.4	49.6
95	80	95.9	7

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 5

Given:

$80%Sn$

Calculations:

From the graph:

For % $β$ = $80−299−2=80.4%$

% Eutectic = $97.5−8097.5−61.9=49.2%$

Thus, by using the expression of eutectic, the required value obtained is 49.2%.

Interpretation Introduction

(f)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $95%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $95%Sn$ is 95.9% and 7.0% respectively.

Explanation of Solution

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 6

Given:

$95%Sn$

Calculations:

For % $β$ = $95−299−2=95.9%$

% Eutectic = $97.5−9597.5−61.9=7.0%$

(Mention Graph)

After Studying the graph of tensile strength vs % $β$ we can conclude that as tensile strength increases to its maximum value of 7800psi at % $β$ = 60%.

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 95% Sn is calculated as 95.9% and 7.0% respectively.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 11, Problem 11.26P

Interpretation Introduction

(a)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $10%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, ingot, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $10%Sn$ is 8.2% and 0% respectively.

Explanation of Solution

Given:

$10%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 1

Calculations:

From the graph,

For % $β$ = $10−299−2$ =8.2%

% Eutectic = 0.

Thus, the evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 10% Sn is calculated as 8.2% and 0% respectively.

Interpretation Introduction

(b)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $20%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $20%Sn$ is 18.6% and 2.3% respectively.

Explanation of Solution

Given:

$20%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 2

Calculations:

From the graph,

For % $β$ = $20−299−2=$ 18.6%

% Eutectic = $50−1961.9−19$ =2.3%

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 20% Sn is calculated as 18.6% and 2.3% respectively.

Interpretation Introduction

(c)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $50%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $50%Sn$ is 49.5% and 72.3% respectively.

Explanation of Solution

Given:

$50%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 3

Calculations:

From the diagram,

For % $β$ = $50−299−2=49.5%$

% Eutectic = $60−1961.9−19=72.3%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 50% Sn is calculated as 49.5% and 72.3% respectively.

Interpretation Introduction

(d)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $60%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire,foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $60%Sn$ is 59.8% and 95.6% respectively.

Explanation of Solution

Given:

$60%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 4

Calculations:

From the graph,

For % $β$ = $60−299−2=59.8%$

% Eutectic = $97.5−1961.9−19=95.6%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 60% Sn is calculated as 59.8% and 95.6% respectively.

Interpretation Introduction

(e)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $80%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $80%Sn$ is 80.4% and 49.2% respectively.

Explanation of Solution

Use spreadsheet to tabulate the % total $β$ and % eutectic micro constituent as in table (1)

Composition of % $Sn$ in entire $Pb−sn$ phase diagram	Tensile Strength ( $MPa$ )	Total % $β$ phase	% Eutectic
10	30	8.2	0
20	40	18.6	2.3
50	50	49.5	72.3
60	60	59.8	95.6
80	70	80.4	49.6
95	80	95.9	7

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 5

Given:

$80%Sn$

Calculations:

From the graph:

For % $β$ = $80−299−2=80.4%$

% Eutectic = $97.5−8097.5−61.9=49.2%$

Thus, by using the expression of eutectic, the required value obtained is 49.2%.

Interpretation Introduction

(f)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $95%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $95%Sn$ is 95.9% and 7.0% respectively.

Explanation of Solution

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 6

Given:

$95%Sn$

Calculations:

For % $β$ = $95−299−2=95.9%$

% Eutectic = $97.5−9597.5−61.9=7.0%$

(Mention Graph)

After Studying the graph of tensile strength vs % $β$ we can conclude that as tensile strength increases to its maximum value of 7800psi at % $β$ = 60%.

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 95% Sn is calculated as 95.9% and 7.0% respectively.

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Answer 5

Chapter 11, Problem 11.26P

Interpretation Introduction

(a)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $10%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, ingot, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $10%Sn$ is 8.2% and 0% respectively.

Explanation of Solution

Given:

$10%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 1

Calculations:

From the graph,

For % $β$ = $10−299−2$ =8.2%

% Eutectic = 0.

Thus, the evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 10% Sn is calculated as 8.2% and 0% respectively.

Interpretation Introduction

(b)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $20%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $20%Sn$ is 18.6% and 2.3% respectively.

Explanation of Solution

Given:

$20%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 2

Calculations:

From the graph,

For % $β$ = $20−299−2=$ 18.6%

% Eutectic = $50−1961.9−19$ =2.3%

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 20% Sn is calculated as 18.6% and 2.3% respectively.

Interpretation Introduction

(c)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $50%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $50%Sn$ is 49.5% and 72.3% respectively.

Explanation of Solution

Given:

$50%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 3

Calculations:

From the diagram,

For % $β$ = $50−299−2=49.5%$

% Eutectic = $60−1961.9−19=72.3%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 50% Sn is calculated as 49.5% and 72.3% respectively.

Interpretation Introduction

(d)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $60%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire,foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $60%Sn$ is 59.8% and 95.6% respectively.

Explanation of Solution

Given:

$60%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 4

Calculations:

From the graph,

For % $β$ = $60−299−2=59.8%$

% Eutectic = $97.5−1961.9−19=95.6%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 60% Sn is calculated as 59.8% and 95.6% respectively.

Interpretation Introduction

(e)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $80%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $80%Sn$ is 80.4% and 49.2% respectively.

Explanation of Solution

Use spreadsheet to tabulate the % total $β$ and % eutectic micro constituent as in table (1)

Composition of % $Sn$ in entire $Pb−sn$ phase diagram	Tensile Strength ( $MPa$ )	Total % $β$ phase	% Eutectic
10	30	8.2	0
20	40	18.6	2.3
50	50	49.5	72.3
60	60	59.8	95.6
80	70	80.4	49.6
95	80	95.9	7

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 5

Given:

$80%Sn$

Calculations:

From the graph:

For % $β$ = $80−299−2=80.4%$

% Eutectic = $97.5−8097.5−61.9=49.2%$

Thus, by using the expression of eutectic, the required value obtained is 49.2%.

Interpretation Introduction

(f)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $95%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $95%Sn$ is 95.9% and 7.0% respectively.

Explanation of Solution

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 6

Given:

$95%Sn$

Calculations:

For % $β$ = $95−299−2=95.9%$

% Eutectic = $97.5−9597.5−61.9=7.0%$

(Mention Graph)

After Studying the graph of tensile strength vs % $β$ we can conclude that as tensile strength increases to its maximum value of 7800psi at % $β$ = 60%.

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 95% Sn is calculated as 95.9% and 7.0% respectively.

Answer 6

Chapter 11, Problem 11.26P

Interpretation Introduction

(a)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $10%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, ingot, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $10%Sn$ is 8.2% and 0% respectively.

Explanation of Solution

Given:

$10%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 1

Calculations:

From the graph,

For % $β$ = $10−299−2$ =8.2%

% Eutectic = 0.

Thus, the evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 10% Sn is calculated as 8.2% and 0% respectively.

Answer 7

Chapter 11, Problem 11.26P

Interpretation Introduction

(a)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $10%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, ingot, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Answer 8

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $10%Sn$ is 8.2% and 0% respectively.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given:

$10%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 1

Calculations:

From the graph,

For % $β$ = $10−299−2$ =8.2%

% Eutectic = 0.

Thus, the evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 10% Sn is calculated as 8.2% and 0% respectively.

Answer 13

Interpretation Introduction

(b)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $20%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $20%Sn$ is 18.6% and 2.3% respectively.

Explanation of Solution

Given:

$20%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 2

Calculations:

From the graph,

For % $β$ = $20−299−2=$ 18.6%

% Eutectic = $50−1961.9−19$ =2.3%

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 20% Sn is calculated as 18.6% and 2.3% respectively.

Answer 14

Interpretation Introduction

(b)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $20%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Answer 15

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $20%Sn$ is 18.6% and 2.3% respectively.

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given:

$20%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 2

Calculations:

From the graph,

For % $β$ = $20−299−2=$ 18.6%

% Eutectic = $50−1961.9−19$ =2.3%

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 20% Sn is calculated as 18.6% and 2.3% respectively.

Answer 20

Interpretation Introduction

(c)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $50%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $50%Sn$ is 49.5% and 72.3% respectively.

Explanation of Solution

Given:

$50%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 3

Calculations:

From the diagram,

For % $β$ = $50−299−2=49.5%$

% Eutectic = $60−1961.9−19=72.3%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 50% Sn is calculated as 49.5% and 72.3% respectively.

Answer 21

Interpretation Introduction

(c)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $50%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Answer 22

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $50%Sn$ is 49.5% and 72.3% respectively.

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given:

$50%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 3

Calculations:

From the diagram,

For % $β$ = $50−299−2=49.5%$

% Eutectic = $60−1961.9−19=72.3%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 50% Sn is calculated as 49.5% and 72.3% respectively.

Answer 27

Interpretation Introduction

(d)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $60%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire,foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $60%Sn$ is 59.8% and 95.6% respectively.

Explanation of Solution

Given:

$60%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 4

Calculations:

From the graph,

For % $β$ = $60−299−2=59.8%$

% Eutectic = $97.5−1961.9−19=95.6%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 60% Sn is calculated as 59.8% and 95.6% respectively.

Answer 28

Interpretation Introduction

(d)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $60%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire,foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Answer 29

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $60%Sn$ is 59.8% and 95.6% respectively.

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given:

$60%Sn$

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 4

Calculations:

From the graph,

For % $β$ = $60−299−2=59.8%$

% Eutectic = $97.5−1961.9−19=95.6%$

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 60% Sn is calculated as 59.8% and 95.6% respectively.

Answer 34

Interpretation Introduction

(e)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $80%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $80%Sn$ is 80.4% and 49.2% respectively.

Explanation of Solution

Use spreadsheet to tabulate the % total $β$ and % eutectic micro constituent as in table (1)

Composition of % $Sn$ in entire $Pb−sn$ phase diagram	Tensile Strength ( $MPa$ )	Total % $β$ phase	% Eutectic
10	30	8.2	0
20	40	18.6	2.3
50	50	49.5	72.3
60	60	59.8	95.6
80	70	80.4	49.6
95	80	95.9	7

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 5

Given:

$80%Sn$

Calculations:

From the graph:

For % $β$ = $80−299−2=80.4%$

% Eutectic = $97.5−8097.5−61.9=49.2%$

Thus, by using the expression of eutectic, the required value obtained is 49.2%.

Answer 35

Interpretation Introduction

(e)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $80%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Answer 36

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $80%Sn$ is 80.4% and 49.2% respectively.

Answer 37

Expert Solution

Answer 38

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Use spreadsheet to tabulate the % total $β$ and % eutectic micro constituent as in table (1)

Composition of % $Sn$ in entire $Pb−sn$ phase diagram	Tensile Strength ( $MPa$ )	Total % $β$ phase	% Eutectic
10	30	8.2	0
20	40	18.6	2.3
50	50	49.5	72.3
60	60	59.8	95.6
80	70	80.4	49.6
95	80	95.9	7

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 5

Given:

$80%Sn$

Calculations:

From the graph:

For % $β$ = $80−299−2=80.4%$

% Eutectic = $97.5−8097.5−61.9=49.2%$

Thus, by using the expression of eutectic, the required value obtained is 49.2%.

Answer 41

Interpretation Introduction

(f)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $95%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $95%Sn$ is 95.9% and 7.0% respectively.

Explanation of Solution

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 6

Given:

$95%Sn$

Calculations:

For % $β$ = $95−299−2=95.9%$

% Eutectic = $97.5−9597.5−61.9=7.0%$

(Mention Graph)

After Studying the graph of tensile strength vs % $β$ we can conclude that as tensile strength increases to its maximum value of 7800psi at % $β$ = 60%.

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 95% Sn is calculated as 95.9% and 7.0% respectively.

Answer 42

Interpretation Introduction

(f)

Interpretation:

The total $β$ % and the % eutectic microconstituent for $95%Sn$ at room temperature needs to be determined.

Concept Introduction:

The compound formula of Lead-Tin alloy is designated by 'Pb-Sn'.

It appears in solid form.

It appears in various shapes like wire, foil, bar, ribbon etc.

It appears in silver color.

Its melting point is 182-215 degree Celsius.

Lead-Tin are widely used as soldering alloys. They are compatible for all types of uses.

Answer 43

Expert Solution

Answer to Problem 11.26P

The Total % $β$ and the % eutectic microconstituent at room temperature for $95%Sn$ is 95.9% and 7.0% respectively.

Answer 44

Expert Solution

Answer 45

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

Essentials Of Materials Science And Engineering, Chapter 11, Problem 11.26P , additional homework tip 6

Given:

$95%Sn$

Calculations:

For % $β$ = $95−299−2=95.9%$

% Eutectic = $97.5−9597.5−61.9=7.0%$

(Mention Graph)

After Studying the graph of tensile strength vs % $β$ we can conclude that as tensile strength increases to its maximum value of 7800psi at % $β$ = 60%.

The evaluated value of % $β$ and the % eutectic microconstituent at room temperature for 95% Sn is calculated as 95.9% and 7.0% respectively.