DESIGN OF MACHINERY
6th Edition
ISBN: 9781260113310
Author: Norton
Publisher: RENT MCG
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Problem 4-9a
The link lengths and offset (a, b, c) and the value of 02 for an offset crank-slider linkage
are defined as 1.4 in, 4 in, 1 in, 45°, respectively. Draw the scaled linkage and graphically
find all possible solutions (both open and crossed) for angle 0z and slide position d.
- slider axis
B
R3
A
R4
offset
R,
04
02
(This is not the scaled kinematic diagram.)
Problem 4-10a
Repeat Problem 4-9a except solve by the vector loop method.
Problem 4-6a
The link lengths (a, b, c, d) and the value of 62 for a crank-rocker linkage are defined as
2, 7, 9, 6, 30°, respectively. Draw the scaled linkage. Find all possible solutions (both
open and crossed) for angles 03 and 04 graphically.
Open
B
3
A
LNCS
4
04
GCS
O4
Crossed
(This is not the scaled kinematic diagram.)
Problem 4-7a
Repeat Problem 4-6a except solve by the vector loop method.
The figure shows a variation of the Scotch-yoke mechanism. It is driven by crank 2 at an angular velocity and acceleration of 36 rad/s ccw and 120 rad/s2 ccw, respectively. Find the velocity and acceleration of the crosshead, link 4.|AO2|=75 mm.
(Using Complex Algebraic approach do the Position Analysis; Velocity Analysis and Acceleration Analysis then solve the problem please)
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- For the mechanism shown in figure. Obtain the angular velocity of link 3 and the slipping velocity between link 3 and link = 5 inches RAO 4 = 4 Using loop closure method. The lengths of links RPA 5î in/sec. LAPO = 90 degrees. 10 inches and VA = 0& TA r₂ 1 "arrow_forwardConsider an offset inverted four-bar slider crank mechanism as shown in the following figure. Determine the angular acceleration of link 3 given L2 = 6 cm, 0₂ = 60°, and other dimensions shown in the figure. 02 = = 70 rad/sec² CCW 0₂ = 90 rpm CW A 3 02 3.0 cm 10.0 cm 4 B3 on 3 B4 on 4arrow_forwardProblem 4-6a The link lengths (a, b, c, d) and the value of 2 for a crank-rocker linkage are defined as 2, 7, 9, 6, 30°, respectively. Draw the scaled linkage. Find all possible solutions (both open and crossed) for angles 03 and 04 graphically. Орen B A LNCS 4 a GCS र 4 4" Crossed (This is not the scaled kinematic diagram.) Problem 4-7a Repeat Problem 4-6a except solve by the vector loop method.arrow_forward
- theta O = 55 The link length and value of O2 for some four bar linkage are defined below, (drive link =4.2 cm , coupler link =5.9 cm , follower link = 5.9 cm, fixed link= 6.85 cm 1. draw the linkage to scale and graphically find all possible solution (both open and cross) for 03 and O4 2. If w = 2 rad /s (CCW) find the angular velocity for bar 3 and 4 3.if a= 5 rad/s? (Ccw) find the normal and tangential acceleration for link 3 and 4arrow_forwardA pinjointed fourbar linkage is shown in the figure below. The link lengths are L1 = 7.8 in., L2 = 2.9 in., L3 = 7.25 in. and L4= 3.5 in. Using the current position, 02-100°, the position analysis has determined that 04 = 214.25°. Currently, link 2 is traveling at 5.50 rad/s CCW Lep B. Figure 6.7 Four-bar linkage acceleration analysis The angular velocities of link 3 w3 and and link 4 Wa are: Select one: O a. w3 = 3.589 rad/s, Wa = -2.91 rad/s O b. w3 = 2.07rad/s, wa = -2.91 rad/s C. W3 = 2.7 rad/s, wa 3.428 rad/s O d. w3 = 2.07 rad/s, w4 = -3.38 rad/sarrow_forwardA mono-cylinder engine has r = 0.3 m, l = 0.9 m, It has: crank mass m2 = 4.5 kg , crank rG2 = 0.4r, conrod mass m3 = 12 kg ,conrod rG3 = 0.3l from A, and piston m4 = 5 kg. The crank is rotating at constant speed ω =3000 rpm. The following equation is an approximation of the gas force over 180° of crank angle with Fgmax = 3000 N and β = 15º.  we need to find the gas force, gas torque, and inertia force . Use approximate expressions in your calculationarrow_forward
- The link length and value of O2 for some four bar linkages are defined below, (fixed link =12 cm, drive link =5 cm, coupler link = 10 cm, follower link= 8 cm) 1. draw the linkage to scale and graphically find all possible solution (both open and cross) for 03 and O4, analytical . 2. If w = 2 rad /s (CCW) find the angular velocity for bar 3 and 4 3.if a= 5 rad/s² (CCW) find the normal and tangential acceleration for link 3 and 4arrow_forwardA general pinjointed fourbar linkage is shown in the figure below. It has the followings: The link lengths are L1 = 8.50 in., L2 = 3.00 in., L3 = 5.00 in. and L4 = 4.50 in. The values of e1 = 0, 02 = 60°, and 04 = 119°. The angular velocity of link2 w2 = 10 rad/s CCW. L4 2 = 60° Ao B. O, = 0° Figure 5.32 Problems 5.3 and 5.4 The angular velocities of link 3 wz and and link 4 wa are: Select one: O a. w3 = 5.29rad/s CW, w4 = 6.14 rad/s CW O b. w3 = 3.94 rad/s CCW, W4 = 4.8 rad/s CCW O c. W3 = 3.94 rad/s CCW, wa = 6.14 rad/s CCW %3D O d. w3 = 5.29 rad/s CW, w4 = 4.80 rad/s CCW %3D %3Darrow_forward12. In the below given quick-return Grashof linkage diagram, the construction angle 8 = 30° and forward stroke rocker angle is 45°. Find the time ratio TR. Show your work. B 2 (0₂ A₂) B2 B₁ KA A₁ By 0₁arrow_forward
- Problem 2 The linkage in Figure P7-5b has o4A = o2A = 0.75, AB = 1.5, and AC = 1.2 in. The effective crank angle in the position shown is 77° and angle BAC = 30°. Find a3, AA, AB, Ac for the position shown for w2 = 15 rad/sec and a2 = 10 rad/sec^2 in the directions shown using an analytic method. (Hint: Create an effective linkage for the position shown and analyze it as a pin-jointed fourbar.) the linkage has a parallelogram form Assume rolling contactarrow_forward–Solve for the required parameters using Instantaneous Center Methodarrow_forwardProblem 2 The linkage in Figure P7-5b has O4A = O2A = 0.75, AB = 1.5, and AC = 1.2 in. The effective crank angle in the position shown is 77° and angle BAC = 30°. Find a3, AA. AB,Ac for the position shown for w2 = 15 rad/sec and a2 = 10 rad/sec^2 in the directions shown using an analytic method. (Hint: Create an effective linkage for the position shown and analyze it as a pin-jointed fourbar.)the linkage has a parallelogram form Assume rolling contactarrow_forward
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