Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 11, Problem 11.11P
To determine
Calculate the primary consolidation settlement of the clay layer.
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For a normally consolidated insensitive clay 0_CD= 30°. Deviator stress at failure of the same soil is 250 kN/m2 in CU test. If Skempton's A-parameter at failure is 0.62, find out the confining pressure during the consolidation state.
a 280
b. 260
c. 270
d. 250
3. For a normally consolidated clay, the
following were recorded; confining
pressure= 03 = 140KPa and Aod=264
KPa. Find Ø.
For the soil profile shown below, estimate the consolidation settlement occur in the clay layer if:
1- Clay is normally consolidated.
2- The oc= 140 kN/m².
175 kN/m?
1.0 m
Sand y=17.5 kN/m³
CR
1.0 m
Sand ysat = 22 kN/m³
Ysat = 22 kN/m
WS
1.0 m
3.0 m
Clay, Ysat = 20 kN/m³, e= 0.55,
Cc= 0.25, C,= 0.05
1.5 m
Silty sand ysat = 19 kN/m³
Chapter 11 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- 5 The compression curve (void ratio, e vs. effective stress, o) for a certain clayey soil is a straight line in a semi-logarithmic plot and it passes through the points (e = 1.2; o = 50 kPa) and (e=0.6; o = 800 kPa). The compression index (up to two decimal places) of the soil is 100arrow_forward4. In a consolidated-drained triaxial test on a clay that is normally consolidated, the results are as follows: O3 = 15 lb/in 2 (Aoa)f = 11 lb/in? (Aua)f = 7.2 lb/in? a) Determine the consolidated-undrained friction angle. %3D b) Calculate the drained friction angle.arrow_forwardThe results of a consolidated undrained test, in which o3 = 392 kN/m?, on a normally consolidated clay are given as: Axial strain (%) Ao(kN/m²) ug(kN/m²) 0.5 0.75 156 196 226 235 250 245 240 235 99 120 132 147 161 170 173 175 1.3 2 3 4 4.5 Draw the K; line in a P' versus q' diagram. Also draw the s tress path for this test in the diagram.arrow_forward
- A soil profile shown is subjected to a load of 48 kN/m2 at the ground surface. The preconsolidation pressure of the clay Pc = 160 kPa. Determine the settlement of the clay layer caused by primary consolidation. Use Cs = 1/5 Cc. 48 kN/m2 ground surface 4m Sand Ys =16 kN/m³ ground water țablę 6m Y sat =18 kN/m³ Clay 3m 6m Ysat =19 kN/m³ Ans. 71 mmarrow_forwardProblem l: For Problem Number 30. A layered soil has the following data; H= 1.5 m k,= 10°cm/sec k2= 3.0 x 10°cm/sec H2= 2.5 m H3= 3.0 m k3= 3.5 x 10°cm/sec 30) Determine the ratio kH(eq)/K vleg). a) 36.80 b) 37.27 c) 35.40 d) 33.90arrow_forwardThe compression curve (void ratio, e vs. effective stress, o) for a certain clayey soil is a straight line in a semi-logarithmic plot and it passes through the points (e = 1.2; o = 50 kPa) and (e = 0.6; o = 800 kPa). The compression index (up to two decimal places) of the soil isarrow_forward
- The following data are given for normally consolidated clay: Thickness=2.6m Primary Cc=0.3 Secondary Cc=0.02 e=0.8 Average Pressure=127 kPa Change in pressure (vertical) =46 kPa Determine the following 1. Primary Consolidation Settlement (Ans. 58.17mm) 2. Secondary Settlement five years after the completion of the primary settlement. The time for completion of primary settlement is 1.5 years. (Ans. 15.4mm)arrow_forwardQ.3. Calculate the total primary consolidation settlement of the soil layres as showr Figure Q3 below. ( 607 )kN EGL Sand Y = 18 kN/m 2m 2 m x 3 m 1 m Assume, Ysat = 18.5 kN/m³ C. = (1/6) Cc for both layers Clay layer-1 eo = 0.92 2 m Cc = 0.154 OCR=1 Silty Sand layer, Ysat = 19 kN/m³ Ysat = 19.5 kN/m³ eo = 0.564 Cc = 0.104 Clay layer-2 3 m OCR=1.6 Pervious Rock layer Figure Q3: Soil Layers Earrow_forwardFor a normally consolidated insensitive clay ∅_CD = 30°. Deviator stress at failure of the same soil is 250 kN/m2 in CU test. If Skempton’s A-parameter at failure is 0.62, find out the confining pressure during the consolidation state. a. 260 b. 270 c. 280 d. 250arrow_forward
- -) A clay stratum has 2.5 m thickness and has initial overburden pressure of 45 kN/m². The clay is over consolidated with a preconsolidation pressure of 65 kN/m². Find the final settlement due to increment of pressure of 55 kN/m² at the middle of clay layer. Use the following data: Initial void ratio = 1.2 Compression index = 0.27 Swelling index = 0.06arrow_forwardFor a normally consolidated insensitive clay ∅_CD = 30°. Deviator stress at failure of the same soil is 250 kN/m2 in CU test. If Skempton’s A-parameter at failure is 0.62, find out the confining pressure during the consolidation state. Show free body diagram a.260 b.250 c.270 d.280arrow_forwardFigure below shows a soil profile. The uniformly distributed load on the ground surface is Δσ. 2Given Δσ = 150 kN/m , compression index (Cc) for clay layer is 0.30, and recompression index (Cs) for clay layer is 0.06. Estimate the primary consolidation settlement if the clay is normally consolidated (NC).Given:H1 =2.5m,H2 =2.5m,andH3 =3.5m.Sand: γdry(sand) = 15 kN/m3; γsat(sand) = 18 kN/m3 Clay: γsat(clay) = 19 kN/m3; Initial void ratio for clay, e0 = 0.65arrow_forward
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