Mathematics All Around (6th Edition)
6th Edition
ISBN: 9780134434681
Author: Tom Pirnot
Publisher: PEARSON
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Chapter 10.CT, Problem 6CT
To determine
To Explain:
The reason why the Huntington–Hill apportionment principle avoids an Alabama paradox.
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Which apportionment paradox may be produced by the Adams' method but not the Webster method?
Jefferson's method, Webster's method, and Adams's method require using a _______ quota.
5. Name the apportionment method in which we round each
group's modified quota to the nearest whole number?
6. Name the paradox. " The addition of a new group changed the
apportionments of other groups"
Chapter 10 Solutions
Mathematics All Around (6th Edition)
Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Prob. 6ECh. 10.1 - Sharpening Your Skills If the American Nurses...Ch. 10.1 - Prob. 8ECh. 10.1 - Sharpening your Skills Which state is more poorly...Ch. 10.1 - Prob. 10E
Ch. 10.1 - Sharpening your Skills Recall that on a 10-member...Ch. 10.1 - Sharpening your Skills Redo Exercise 11 for Aroco...Ch. 10.1 - Sharpening your Skills Apportioning...Ch. 10.1 - Sharpening your Skills Apportioning...Ch. 10.1 - Applying What Youve Learned The Alabama paradox....Ch. 10.1 - Applying What Youve Learned The Alabama paradox....Ch. 10.1 - Applying What Youve Learned The Alabama paradox...Ch. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.2 - Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.3 - In Exercises 1-4, we give you a total population,...Ch. 10.3 - Prob. 2ECh. 10.3 - In Exercises 1-4, we give you a total population,...Ch. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Use the Jefferson method to assign the seats on...Ch. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Choosing representatives on a negotiations...Ch. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Use the Webster method to apportion the members of...Ch. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Use the Webster method to assign the number of...Ch. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - Exercises 33-36Illustrate that the Jefferson and...Ch. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 43ECh. 10.3 - Prob. 44ECh. 10.3 - Prob. 45ECh. 10.3 - Prob. 46ECh. 10.3 - Prob. 47ECh. 10.4 - Identify each situation as dealing with either...Ch. 10.4 - Identify each situation as dealing with either...Ch. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 4ECh. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - In Exercises 15 and 16, use the method of sealed...Ch. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.CR - Prob. 1CRCh. 10.CR - Prob. 2CRCh. 10.CR - Prob. 3CRCh. 10.CR - Prob. 4CRCh. 10.CR - Prob. 5CRCh. 10.CR - Prob. 6CRCh. 10.CR - Prob. 7CRCh. 10.CR - Prob. 8CRCh. 10.CR - Prob. 9CRCh. 10.CR - Prob. 10CRCh. 10.CR - Prob. 11CRCh. 10.CR - Prob. 12CRCh. 10.CR - Prob. 13CRCh. 10.CR - Prob. 14CRCh. 10.CR - Prob. 15CRCh. 10.CR - Prob. 16CRCh. 10.CT - What is the Alabama paradox?Ch. 10.CT - Suppose state C has a population of 1,640,000 and...Ch. 10.CT - The Metropolitan Community College Arts Council...Ch. 10.CT - Prob. 4CTCh. 10.CT - Suppose that Arizona has a population of 5.23...Ch. 10.CT - Prob. 6CTCh. 10.CT - Prob. 7CTCh. 10.CT - Prob. 8CTCh. 10.CT - Prob. 9CTCh. 10.CT - Prob. 10CTCh. 10.CT - Prob. 11CTCh. 10.CT - Prob. 12CTCh. 10.CT - Prob. 13CTCh. 10.CT - Prob. 14CTCh. 10.CT - Three brothersLarry, Moe, and Curlyare dissolving...
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- 9. A grant and a newly passed levy will allow a county to buy 13 new fire trucks for its fire precincts. The new trucks are going to be allotted to the precincts based on the number of times each precinct had to respond to calls in the last six months. Use the Hamilton Apportionment Plan and the table below to determine the number of fire trucks each precinct will receive. District Number of Calls D-1 45 D-2-1 73 D-2-2 100 D-3 67 D-4-1 179 D-4-2 95arrow_forwardQUESTION 12 Which method of apportionment always satisfies the quota condition? OA. Hill-Huntington B. Jefferson OC. Hamilton OD. Websterarrow_forwardIf after apportionment, the total seats apportioned exceeds the total possible apportionment, What must be done to the standard divisor to lower the seats apportioned? It should not be changed. O It cannot be determined. O It must be decreased. O It must be increased.arrow_forward
- Use Adamss's method of apportionment to solve the following problem. 1. Suppose a nation has 6 states, with populations shown in the chart below. The representative body had 200 seats. Find: the standard divisor, the modified divisor, and the distribution of representatives to each state. Then complete the table. Round all standard and modified quotas to 7 decimal places if needed. You can use a spreadsheet to help you figure out an answer or calculate using a calculator. Representative Seats State E F Total Standard Divisor Modified Divisor 200 Population Standard Rounded Modified Quotas Up Quotas Quotas 1,598,400 1,236,300 5,460,200 826,900 965,500 1,112,700 11,200,000 Modified Upper Quotasarrow_forwardUse Adamss's method of apportionment to solve the following problem. 1. Suppose a nation has 6 states, with populations shown in the chart below. The representative body had 200 seats. Find: the standard divisor, the modified divisor, and the distribution of representatives to each state. Then complete the table. Round all standard and modified quotas to 7 decimal places if needed. You can use a spreadsheet to help you figure out an answer or calculate using a calculator. Representative Seats 200 Rounded Modified Modified Upper Quotas State Population Standard Quotas Up Quotas Quotas 1,598,400 1,236,300 5,460,200 826,900 965,500 1,112,700 11,200,000 А В C F Total Standard Divisor Modified Divisorarrow_forwardUse Webster's method of apportionment to solve the following problem. 2. Suppose a nation has 5 states, with populations shown in the chart below. The representative body had 150 seats. Find: the standard divisor, the modified divisor, and the distribution of representatives to each state. Then complete the table. Round all standard and modified quotas to 7 decimal places if needed. You can use a spreadsheet to help you figure out an answer or calculate using a calculator. Representative Seats 150 State Population Standard Rounded Modified Modified Quotas Quotas Quotas Rounded Quotas A 1,895,500 1,234,500 845,200 В C 399,120 500,680 4,875,000 D E Total Standard Divisor Modified Divisorarrow_forward
- Consider the following apportionment problem. North: 1,820,000 Northeast: 2,950,000 East: 1,760,000 Southeast: 1,980,000 South: 1,200,000 Southwest: 2,480,000 West: 3,300,000 Northwest: 1,140,000 If there are to be 475 representatives, use the apportionment plan requested below. Hamilton's plan North Northeast East Southeast South Southwest West Northwestarrow_forwardIn a small Vermont town of 5,000 adults, 2,000 live in private homes while the remaining live in apartment buildings. Of those living in private homes, 240 are upper income, 1,200 are middle income and 560 are lower income. Of those living in apartment buildings, 900 are upper income, 600 are middle income, and 1,500 are lower income. The town council is interested in making a policy change to restructure the property tax base in the town and needs to make an informed decision based on demographic trends and real data. Set up a cross-classification table for type of dwelling unit and income status and find the probability that a person chosen at random: a. Is middle incomeb. Lives in an apartment buildingc. Lives in a private home and is upper incomed. Lives in an apartment building or is lower incomee. Is middle income, if it is known that he lives in an apartment buildingarrow_forwardUse Webster's method of apportionment to solve the following problem. 2. Suppose a nation has 5 states, with populations shown in the chart below. The representative body had 150 seats. Find: • the standard divisor, the modified divisor, and • the distribution of representatives to each state. Then complete the table. Round all standard and modified quotas to 7 decimal places if needed. You can use a spreadsheet to help you figure out an answer or calculate using a calculator. Representative Seats State A B C Total Standard Divisor Modified Divisor 150 Population 1,895,500 1,234,500 845,200 399.120 500.680 4,875,000 Standard Rounded Modified Modified Quotas Quotas Rounded Quotas Quotasarrow_forward
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