Chapter 10.5, Problem 6CE

To determine

To find: the position of the center of circle with respect to $\overline{AB}$ .

Answer to Problem 6CE

Center of the circle lies on perpendicular bisector of $AB$ .

Explanation of Solution

Given Information:

Given figure,

  

Calculation:

Find the position of center with respect to $AB$ ,

Join $A$ and $B$ ,

Take a point $K$ on line $t$ such that $A,B$ and $K$ are not collinear and draw $BK$ .

Draw perpendicular bisector of $AB$ and $BK$ and name point of intersection of perpendicular bisector as $O$ .

Take $OA$ as radius and draw circle with center $O$ ,

Observe that, Center of the circle lies on perpendicular bisector of $AB$ .