Explanation Formula Used: The general equation of a hyperbola with center at ( h , k ) , foci ( h ± c , k ) , vertices ( h ± a , k ) and asymptotes y − k = ± b a ( x − h ) is given by, ( x − h ) 2 a 2 − ( y − k ) 2 b 2 = 1 , where c 2 = a 2 + b 2 . Calculation: The hyperbola has vertices at ( ± 3 , 0 ) and asymptotes y = ± 2 x . Thus, ( h ± a , k ) = ( ± 3 , 0 ) and asymptote y = ± 2 x is of the form y − k = ± b a ( x − h ) . That is, h = 0 , a = 3 and k = 0

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ISBN: 9781337613927

Author: Stewart

Publisher: CENGAGE L

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Chapter 10.5, Problem 49E

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The equation for the hyperbola using vertices (±3,0) and asymptotes y=±2x.

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Chapter 10.5, Problem 48E

Chapter 10.5, Problem 50E

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The equation for the hyperbola using vertices ( ± 3 , 0 ) and asymptotes y = ± 2 x .

Solution Summary: The author explains the equation for a hyperbola using vertices at (pm 3,0) and asymptotes.

The equation for the hyperbola using vertices (±3,0) and asymptotes y=±2x.

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