Explanation Formula used: The graphs of the form y = a sin ( b x + c ) has amplitude | a | , the period 2 π b and displacement is − c b . Calculation: For a point on the string, the displacement is given by, y = A sin 2 π ( t T − x λ ) . Given that, A = 0.350 in . , T = 0.250 s , λ = 24.0 in . and x = 20.00 in . Substitute A = 0.350 in . , T = 0.250 s , λ = 24.0 in . and x = 20.00 in in y = A sin 2 π ( t T − x λ ) as, y = 0.350 sin 2 π ( t 0.250 − 20.00 24.0 ) = 0.350 sin 2 π ( 4 t − 5 6 ) = 0.350 sin ( 8 π t − 5 π 3 ) That is, y = 0.350 sin ( 8 π t − 5 π 3 ) . The amplitude of y = 0.350 sin ( 8 π t − 5 π 3 ) is 0

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ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 10.5, Problem 16E

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To sketch: The two cycles of the displacement y as a function of time t for A=0.350 in.,T=0.250 s,λ=24.0 in. and x=20.00 in.

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Chapter 10.5, Problem 15E

Chapter 10.5, Problem 17E

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Chapter 10 Solutions

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Ch. 10.1 - For the graph of y = −6 sin x, set up a table of...Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - In Exercises 3–6, complete the following table for...Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - In Exercises 7–22, give the amplitude and sketch...Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E

Ch. 10.1 - Prob. 10E Ch. 10.1 - Prob. 11E Ch. 10.1 - Prob. 12E Ch. 10.1 - In Exercises 7–22, give the amplitude and sketch...Ch. 10.1 - In Exercises 7–22, give the amplitude and sketch...Ch. 10.1 - Prob. 15E Ch. 10.1 - Prob. 16E Ch. 10.1 - Prob. 17E Ch. 10.1 - Prob. 18E Ch. 10.1 - Prob. 19E Ch. 10.1 - Prob. 20E Ch. 10.1 - Prob. 21E Ch. 10.1 - Prob. 22E Ch. 10.1 - Prob. 23E Ch. 10.1 - Prob. 24E Ch. 10.1 - Prob. 25E Ch. 10.1 - Prob. 26E Ch. 10.1 - Prob. 27E Ch. 10.1 - Prob. 28E Ch. 10.1 - Prob. 29E Ch. 10.1 - Prob. 30E Ch. 10.1 - Prob. 31E Ch. 10.1 - In Exercises 27–32, solve the given problems. 32....Ch. 10.1 - Prob. 33E Ch. 10.1 - Prob. 34E Ch. 10.1 - Prob. 35E Ch. 10.1 - Prob. 36E Ch. 10.1 - Prob. 37E Ch. 10.1 - Prob. 38E Ch. 10.1 - Prob. 39E Ch. 10.1 - Prob. 40E Ch. 10.2 - Prob. 1PE Ch. 10.2 - Prob. 2PE Ch. 10.2 - Prob. 3PE Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - In Exercises 3–22, find the amplitude and period...Ch. 10.2 - Prob. 5E Ch. 10.2 - In Exercises 3–22, find the amplitude and period...Ch. 10.2 - 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The two cycles of the displacement y as a function of time t for A = 0.350 in . , T = 0.250 s , λ = 24.0 in . and x = 20.00 in .

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To sketch: The two cycles of the displacement y as a function of time t for A=0.350 in.,T=0.250 s,λ=24.0 in. and x=20.00 in.

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Chapter 10 Solutions