Chapter 10.3, Problem 9Q

a.

To determine

To calculate:

The probability of the female student that choose random from the surveyed, eats fruit every day.

Answer to Problem 9Q

The probability of the female student that choose random from the surveyed, eats fruit every day is $0.595$ .

Explanation of Solution

Given information:

  

Calculation:

  

The data from the histogram as follows:

Number of $13$ years old male who eat fruits $=60$

Number of $13$ years old female who eat fruits $=61$

Number of $15$ years old male who eat fruits $=53$

Number of $15$ years old female who eat fruits $=58$

Now, the probability that any randomly selected women, of any age group will have a fruit every day is obtained as follows:

  $\begin{array}{l}P\left(femalestudenteatsfruiteveryday\right)\\ =\frac{119}{200}\\ =0.595\end{array}$

Thus, the required probability of the female student that choose random from the surveyed, eats fruit every day is $0.595$ .

b.

To determine

To calculate:

The probability of the $15$ year old student that choose random from the surveyed, eats fruit every day.

Answer to Problem 9Q

The probability of the $15$ year old student that choose random from the surveyed, eats fruit every day is $0.555$ .

Explanation of Solution

Given information:

  

Calculation:

  

The data from the histogram as follows:

Number of $13$ years old male who eat fruits $=60$

Number of $13$ years old female who eat fruits $=61$

Number of $15$ years old male who eat fruits $=53$

Number of $15$ years old female who eat fruits $=58$

Now, the event being observed is that at random selecting a $15$ year old student will eat fruit every day is obtained as,

  $\begin{array}{l}P\left(15yearoldeatsfruit\right)\\ =\frac{111}{200}\\ =0.555\end{array}$

Thus, the probability of the $15$ year old student that choose random from the surveyed, eats fruit every day is $0.555$ .