EBK MECHANICS OF MATERIALS
7th Edition
ISBN: 8220102804487
Author: BEER
Publisher: YUZU
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 10.3, Problem 57P
Using allowable stress design, determine the allowable centric load for a column of 6-m effective length that is made from the following rolled-steel shape: (a) W200 × 35.9, (b) W200 × 86. Use σY = 250 MPa and E = 200 GPa.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
1. A 60-mm diameter steel tube with a wall thickness of 3 mm just fits in a rigid hole. Determine the
tangential stress developed if an axial compressive load of 12 kN is applied. Use v = 0.30 and E = 200 GPa.
Answer: 0 = 6.37 MPa
2. A 200-mm long bronze tube closed at both ends fits without clearance in a 70-mm hole in a rigid block.
It has a diameter of 70 mm and a wall thickness of 5 mm. The tube then sustained an internal pressure
of 4.5 MPa. Use v = 0.33 and E= 83 GPa. Compute the tangential stress in the tube. Answer: Ot =
5.20 MPa
An axial load of 5000 kN is to be
supported by short reinforced concrete
column 400 mm x 500 mm with 5 m length.
It has six steel rods of 28 mm ø as
reinforcement. E = 200 GPa for steel
and 10 GPa for concrete.
8.
Determine the stress for concrete.
9.
Calculate the stress for steel.
Two solid cylindrical rods support a load of P = 27 kN as shown. Rod (1) has a diameter of 17 mm, and the diameter of rod (2) is 12
mm. Determine the axial stress in rod (1).
3.8 m
4.6 m
(1)
5.6 m
3.3 m
125.7 MPa
96.7 MPa
59.1 MPa
104.1 MPa
79.9 MPa
B
(2)
Chapter 10 Solutions
EBK MECHANICS OF MATERIALS
Ch. 10.1 - Knowing that the spring at A is of constant k and...Ch. 10.1 - Two rigid bars AC and BC are connected by a pin at...Ch. 10.1 - 10.3 and 10.4 Two rigid bars AC and BC are...Ch. 10.1 - 10.3 and 10.4 Two rigid bars AC and BC are...Ch. 10.1 - The steel rod BC is attached to the rigid bar AB...Ch. 10.1 - The rigid rod AB is attached to a hinge at A and...Ch. 10.1 - The rigid bar AD is attached to two springs of...Ch. 10.1 - A frame consists of four L-shaped members...Ch. 10.1 - Determine the critical load of a pin-ended steel...Ch. 10.1 - Determine the critical load of a pin-ended wooden...
Ch. 10.1 - A column of effective length L can be made by...Ch. 10.1 - A compression member of 1.5-m effective length...Ch. 10.1 - Determine the radius of the round strut so that...Ch. 10.1 - Determine (a) the critical load for the square...Ch. 10.1 - A column with the cross section shown has a...Ch. 10.1 - A column is made from half of a W360 216...Ch. 10.1 - A column of 22-ft effective length is made by...Ch. 10.1 - A single compression member of 8.2-m effective...Ch. 10.1 - Knowing that P = 5.2 kN, determine the factor of...Ch. 10.1 - Members AB and CD are 30-mm-diameter steel rods,...Ch. 10.1 - The uniform brass bar AB has a rectangular cross...Ch. 10.1 - A 1-in.-square aluminum strut is maintained in the...Ch. 10.1 - A 1-in.-square aluminum strut is maintained in the...Ch. 10.1 - Column ABC has a uniform rectangular cross section...Ch. 10.1 - Column ABC has a uniform rectangular cross section...Ch. 10.1 - Column AB carries a centric load P of magnitude 15...Ch. 10.1 - Each of the five struts shown consists of a solid...Ch. 10.1 - A rigid block of mass m can be supported in each...Ch. 10.2 - An axial load P = 15 kN is applied at point D that...Ch. 10.2 - An axial load P is applied to the 32-mm-diameter...Ch. 10.2 - The line of action of the 310-kN axial load is...Ch. 10.2 - Prob. 32PCh. 10.2 - An axial load P is applied to the 32-mm-square...Ch. 10.2 - Prob. 34PCh. 10.2 - Prob. 35PCh. 10.2 - Prob. 36PCh. 10.2 - Solve Prob. 10.36, assuming that the axial load P...Ch. 10.2 - The line of action of the axial load P is parallel...Ch. 10.2 - Prob. 39PCh. 10.2 - Prob. 40PCh. 10.2 - The steel bar AB has a 3838-in. square cross...Ch. 10.2 - For the bar of Prob. 10.41, determine the required...Ch. 10.2 - A 3.5-m-long steel tube having the cross section...Ch. 10.2 - Prob. 44PCh. 10.2 - An axial load P is applied to the W8 28...Ch. 10.2 - Prob. 46PCh. 10.2 - A 100-kN axial load P is applied to the W150 18...Ch. 10.2 - A 26-kip axial load P is applied to a W6 12...Ch. 10.2 - Prob. 49PCh. 10.2 - Axial loads of magnitude P = 84 kN are applied...Ch. 10.2 - An axial load of magnitude P = 220 kN is applied...Ch. 10.2 - Prob. 52PCh. 10.2 - Prob. 53PCh. 10.2 - Prob. 54PCh. 10.2 - Axial loads of magnitude P = 175 kN are applied...Ch. 10.2 - Prob. 56PCh. 10.3 - Using allowable stress design, determine the...Ch. 10.3 - Prob. 58PCh. 10.3 - Prob. 59PCh. 10.3 - A column having a 3.5-m effective length is made...Ch. 10.3 - Prob. 61PCh. 10.3 - Bar AB is free at its end A and fixed at its base...Ch. 10.3 - Prob. 63PCh. 10.3 - Prob. 64PCh. 10.3 - A compression member of 8.2-ft effective length is...Ch. 10.3 - A compression member of 9-m effective length is...Ch. 10.3 - A column of 6.4-m effective length is obtained by...Ch. 10.3 - A column of 21-ft effective length is obtained by...Ch. 10.3 - Prob. 69PCh. 10.3 - Prob. 70PCh. 10.3 - Prob. 71PCh. 10.3 - Prob. 72PCh. 10.3 - Prob. 73PCh. 10.3 - For a rod made of aluminum alloy 2014-T6, select...Ch. 10.3 - Prob. 75PCh. 10.3 - Prob. 76PCh. 10.3 - A column of 4.6-m effective length must carry a...Ch. 10.3 - A column of 22.5-ft effective length must carry a...Ch. 10.3 - Prob. 79PCh. 10.3 - A centric load P must be supported by the steel...Ch. 10.3 - A square steel tube having the cross section shown...Ch. 10.3 - Prob. 82PCh. 10.3 - Prob. 83PCh. 10.3 - Two 89 64-mm angles are bolted together as shown...Ch. 10.3 - Prob. 85PCh. 10.3 - Prob. 86PCh. 10.3 - Prob. 87PCh. 10.3 - Prob. 88PCh. 10.4 - An eccentric load is applied at a point 22 mm from...Ch. 10.4 - Prob. 90PCh. 10.4 - Prob. 91PCh. 10.4 - Solve Prob. 10.91 using the interaction method and...Ch. 10.4 - A column of 5.5-m effective length is made of the...Ch. 10.4 - Prob. 94PCh. 10.4 - A steel compression member of 9-ft effective...Ch. 10.4 - Prob. 96PCh. 10.4 - Two L4 3 38-in. steel angles are welded together...Ch. 10.4 - Solve Prob. 10.97 using the interaction method...Ch. 10.4 - A rectangular column is made of a grade of sawn...Ch. 10.4 - Prob. 100PCh. 10.4 - Prob. 101PCh. 10.4 - Prob. 102PCh. 10.4 - Prob. 103PCh. 10.4 - Prob. 104PCh. 10.4 - A steel tube of 80-mm outer diameter is to carry a...Ch. 10.4 - Prob. 106PCh. 10.4 - Prob. 107PCh. 10.4 - Prob. 108PCh. 10.4 - Prob. 109PCh. 10.4 - Prob. 110PCh. 10.4 - Prob. 111PCh. 10.4 - Prob. 112PCh. 10.4 - Prob. 113PCh. 10.4 - Prob. 114PCh. 10.4 - Prob. 115PCh. 10.4 - A steel column of 7.2-m effective length is to...Ch. 10 - Determine (a) the critical load for the steel...Ch. 10 - Prob. 118RPCh. 10 - Prob. 119RPCh. 10 - (a) Considering only buckling in the plane of the...Ch. 10 - Member AB consists of a single C130 3 10.4 steel...Ch. 10 - The line of action of the 75-kip axial load is...Ch. 10 - Prob. 123RPCh. 10 - Prob. 124RPCh. 10 - A rectangular column with a 4.4-m effective length...Ch. 10 - Prob. 126RPCh. 10 - Prob. 127RPCh. 10 - Prob. 128RP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A steel bar ABCD consists of three sections: AB is of 20mm diameter and 200 mm long, BC is 25 mm square and 400 mm long, and CD is of 12 mm diameter and 200mm long. The bar is subjected to an axial compressive load which induces a stress of 30 MN/m2 on the largest cross-section. Determine the total decrease in the length of the bar when the load is applied. For steel E = 210GN/m2.arrow_forward1. A bronze bar is fastened between a steel bar and an aluminum bar as shown. Axial loads are applied at the positions indicated. Find the largest value of P that will not exceed an overall deformation of 3.0 mm, or the following stresses: 140 MPa in the steel, 120 MPa in the bronze, and 80 MPa in the aluminum. Assume that the assembly is suitably braced to prevent buckling. Use EsT=200GPA, EAL = 70 GPa, and EBr = 83 GPa. As = 480 mm? Ab=650 mm? Al= 320 mm? 2P 4P 3P 1m 2m 1.5marrow_forwardEight steel cables (with equal distance to each other) are supporting a circular heavy moulding of diameter 3m from an overhead point. If the moulding weighs 5 kN/m and the attachment point is 4m above it, determine the following:a. Calculate the tension of the cable.b. Determine the diameter of the wire if the allowable stress is 125 MPa.c. If the diameter of the cable is 10 mm, find the deflection of the steel cable.d. If the diameter of the cable is 10 mm, find the vertical displacement of the molder.arrow_forward
- A rectangular column is made of a grade of sawn wood that has an adjusted allowable stress for compression parallel to the grain oc = 8.3 MPa and a modulus of elasticity E= 11.1 GPa. Using the allowable-stress method, determine the largest allowable effective length L that can be used. Take P= 105 kN. (Round the final answer to two decimal places.) 180 mm 240 mm D y 25 mm The largest allowable effective length L that can be used is 4.81 m.arrow_forwardA 75 mm diameter compound bar is constructed by shrinking a circular brass bush onto the outside of a 50 mm diameter solid steel rod. If the compound bar is then subjected to an axial compressive load of 160 kN determine the load carried by the steel rod and the brass bush and the compressive stress set up in each material. For steel, E = 210 GN/m2; for brass, £ = 100 GN/m2arrow_forwardA rectangular column is made of a grade of sawn wood that has an adjusted allowable stress for compression parallel to the grain σC = 8.3 MPa and a modulus of elasticity E = 11.1 GPa. Using the allowable-stress method, determine the largest allowable effective length L that can be used. Take P = 88 kN. (Round the final answer to two decimal places.) The largest allowable effective length L that can be used is m.arrow_forward
- Prarrow_forwardA tie rod of ¼ inch diameter is used to hold a plaster wall in place. The tensile stress in the rod caused by load P is 20 ksi. Find the diameter “d” (to the nearest 1/6 inch) of the washer that keeps the bearing stress between the plaster and the washer from exceeding 300 psi.arrow_forward7. The rigid slab which weighs 600 kN is supported by three rods of the same cross-section and material. The lower ends of the rods prior to slab attachment were of the same level. Calculate the tensile force in each rod. Answer: PA = 239 KN B с A 6 m 5 m +2 m 600 KN 8. The homogeneous rod of uniform cross-section is attached to rigid supports. The rod is then subjected to axial load P as indicated in the figure. Prove that the reactions are given by R₁ = Pb/ L and R₂ = Pa/ L. R₁ R₂ P a b 4 m L 6 marrow_forward
- Axial loads are applied with rigid bearing plates to the solid cylindrical rods shown. The normal stress in aluminum rod (1) must be limited to 19 ksi, the normal stress in brass rod (2) must be limited to 23 ksi, and the normal stress in steel rod (3) must be limited to 12 ksi. Determine the minimum diameter required for each of the three rods. Assume P = 8 kips, Q = 6 kips, R = 20 kips and S = 21 kips. A D First: Calculate the internal force (positive if tensile, negative if compresive) in rod (1). Use a FBD cutting through the rod in the section that includes the free end A. Answer: F₁ = i kips. (2) (3) O B Carrow_forwardAxial loads are applied with rigid bearing plates to the solid cylindrical rods shown. The normal stress in aluminum rod (1) must be limited to 19 ksi, the normal stress in brass rod (2) must be limited to 24 ksi, and the normal stress in steel rod (3) must be limited to 14 ksi. Determine the minimum diameter required for each of the three rods. Assume P = 8 kips, Q = 4 kips, R = 16 kips and S = 28 kips. A (1) VQ В R| (2) S S C (3) D First: Calculate the internal force (positive if tensile, negative if compresive) in rod (1). Use a FBD cutting through the rod in the section that includes the free end A.arrow_forwardAxial loads are applied with rigid bearing plates to the solid cylindrical rods shown. The normal stress in aluminum rod (1) must be limited to 20 ksi, the normal stress in brass rod (2) must be limited to 24 ksi, and the normal stress in steel rod (3) must be limited to 12 ksi. Determine the minimum diameter required for each of the three rods. Assume P = 8 kips, Q = 5 kips, R = 20 kips and S = 28 kips. Calculate F1, F2, F3 and..arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
EVERYTHING on Axial Loading Normal Stress in 10 MINUTES - Mechanics of Materials; Author: Less Boring Lectures;https://www.youtube.com/watch?v=jQ-fNqZWrNg;License: Standard YouTube License, CC-BY